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3 years ago

The difference between ionic covalent and metallic bonding

1 answer:

7 0

Ionic: transfer of electrons
Covalent: sharing of electrons
Metallic: sharing of free electrons in a structure of cations

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1.05 g of sodium metal is added to a 50.0 mL solution of 1.00 M hydrochloric acid solution. Sodium chloride and hydrogen gas are

olganol [36]

Answer:

Sodium chloride and hydrogen gas are the products of this reaction. If the gas collected has a pressure of 1.05 atm at 298 K, then what volume is the hydrogen

Explanation:

8 0

2 years ago

What is the half life of the graphed material?

daser333 [38]

Answer:

3 hours

Explanation:

To know the the correct answer to the question given above, it is important we know the definition of half-life.

The half-life of a substance is simply defined as the time taken for half the substance to decay.

Considering the diagram given above, the initial mass of the substance is 100 g.

Half of the initial mass = 100 / 2 = 50 g

Now, we shall determine the time from the graph taken to get to 50 g.

Considering the diagram given above, the time taken to get to 50 g is 3 hours.

Therefore, the half-life of the material is 3 hours.

3 0

2 years ago

How will you prepare 10mL of 0.050M HCl from a 0.10M solution of HCl

vichka [17]

M₁V₁ = M₂V₂

(0.050M)*(10 mL) = (0.10M)*(x)

x = 5 mL

You would take 5 mL of the 0.10 M solution of HCl and add 5 mL of deionized water. Therefore, the total volume will be 10 mL and it will have a molarity of 0.050.

7 0

2 years ago

For the reaction below, Kp = 1.59 at 100°C. If 1.0 g of SrCO3 is placed in an empty 5.00 L reactor and allowed to reach equilibr

Sergio [31]

Answer:

$p_{CO_2}^{eq}=1.59atm$

Explanation:

Hello, in this case, one could consider the undergoing chemical reaction as:

$SrCO_3(s)\rightleftharpoons SrO(s)+CO_2(g)$

Thus, since 1.0 g of strontium carbonate is placed, the equilibrium equation takes the following form, excluding the solid-stated species and considering just the carbon dioxide as it is gaseous:

$Kp=p_{CO_2}^{eq}=1.59atm$

Hence, since at the beginning there is no carbon dioxide, its pressure at equilibrium equals Kp:

$Kp=p_{CO_2}^{eq}=1.59atm$

Which was clearly defined above.

Best regards.

8 0

2 years ago

What is a major problem with CFCs?

oksian1 [2.3K]

The major problem with CFCs is that It is a greenhouse gas, Option A is correct.

Chlorofluorocarbons (CFCs) are nontoxic, nonflammable chemicals containing atoms of carbon, chlorine, and fluorine.

They are used in the manufacture of aerosol sprays, blowing agents for foams and packing materials, as solvents, and as refrigerants.

CFCs are classified as halocarbons, a class of compounds that contain atoms of carbon and halogen atoms

The major problem with CFC's is that they are green house gases

It destroys ozone in the upper atmosphere (stratosphere).

CFCs can produce more than 10,000 times as much warming, pound for pound, once they are in the air.

It is not only because of their dramatic warming potential but also

They were found to be the primary cause of the rapidly escalating destruction of the Earth’s ozone layer,

which protects the planet from dangerous, cancer-causing levels of ultraviolet radiation.

Therefore The major problem with CFCs is that It is a greenhouse gas, Option A is correct.

To know more about CFC'S

brainly.com/question/14330630

#SPJ1

6 0

1 year ago