Answer:
After 18 hours, the amount of pure technetium that will be remaining is 12.5 grams
Explanation:
To solve the question, we note that the equation for half life is as follows;
Where:
N(t) = Quantity of the remaining substance = Required quantity
N₀ = Initial radioactive substance quantity = 100 g
t = Time duration = 18 hours
= Half life of the radioactive substance = 6 hours
Therefore, plugging in the values, we have;
Therefore, after 18 hours, the amount of pure technetium that will be remaining = 12.5 grams.
Answer:
Down is the recipe for momo..
Explanation:
recipe..
. Sieve the wheat flour carefully to remove lumps.
. Add water and knead the flour well to prepare a dough
. Remove the skin of the boiled potato ,cut into small pieces
. Heat the cooking oil in frying pan, and fry the pieces of onions cabbage green chili tomato pea etc.
. Prepare a mix veg stuffing by mixing potato other vegetables , green coriander and salt.
. Prepare a small balls of dough and roll it out of belna.
. Put 10 gm of mix vegetables stuff in the center of rolled dough and close it from all the sides to make a small ball.
. steam the momo for 10-15 minutes. After that it will be ready to serve.
. A sauce or pickle is usually eaten with momo.
Answer:
The number of Aluminium atoms present in per cubic meter is 
Explanation:
Given the density of Aluminium 
is 
And the atomic weight of Aluminium 
is 
Also, the Avogadro's number 
is 
We need to find the number of atoms per cubic meter 
Plug the given values in the formula we get,
So, the number of Aluminium atoms present in per cubic meter is 
Answer:
According to mass and volume, block density is 2 g/ml
Explanation:
Density is a measure, usually used in physics and chemistry, that relates the mass and volume of a solid or compound.
In general terms, the density is directly proportional to the mass, and inversely proportional to the volume, so increasing the mass will also increase the density.
The formula used to calculate the density is
ρ = 
Therefore, according to the mass and density of the block
ρ = 
= 2g/ml
Being the density of the block equal to 2 g/ml.
<em>The other options are not possible, because the values given do not correspond to the result of the equation.</em>
First, we write the reaction equation:
2KI + PbNO₃ → K₂NO₃ + PbI₂
The molar ratio of KI to PbNO₃ is 2 : 1
Moles of PbNO₃ present:
Moles = concentration (M) x volume (dm³)
= 0.194 x 0.195
= 0.038
Moles of KI required = 2 x 0.038 = 0.076 moles
concentration = moles / volume
volume = moles / concentration
= 0.076 / 0.2
= 0.38 L = 380 ml
