I think it's C. Visual Programming
but I'm not 100% sure
The part of a door frame that comes in contact with the door is the jamb
Answer:
(a) 
= 
Explanation:
To convert from binary to hexadecimal, convert each 4 binary digits to its hexadecimal equivalent according to the following;
<em>Binary => Hex</em>
0000 => 0
0001 => 1
0010 => 2
0011 => 3
0100 => 4
0101 => 5
0110 => 6
0111 => 7
1000 => 8
1001 => 9
1010 => A
1011 => B
1100 => C
1101 => D
1110 => E
1111 => F
(a) 1100 1111 0101 0111
=> Taking the first four binary digits : 1100
According to the table, the hexadecimal equivalent is C
=> Taking the second four binary digits : 1111
According to the table, the hexadecimal equivalent is F
=> Taking the third four binary digits : 0101
According to the table, the hexadecimal equivalent is 5
=> Taking the last four binary digits : 0111
According to the table, the hexadecimal equivalent is 7
Therefore, the hexadecimal representation of
1100 1111 0101 0111 is CF57
Answer:
"void" is the correct answer for the given question.
Explanation:
In the function body the value of balance variable is not return that means we use void return type .The void return type is used when the function does not return any value .
If the function are int return type that means it return "integer value ".
if the function are double return type that means it return the "double value" .
The complete implementation of this method is
public void deposit(double amount) // function definition
{
balance = balance + amount; // statement
}
Answer:
The C++ code is given below with appropriate comments
Explanation:
//Remove this header file if not using visual studio.
#include "stdafx.h"
//Include the required header files.
#include <iostream>
//Use for maths function.
#include <cmath>
using namespace std;
//Define main function
int main()
{
// Define the variables
double targetValue = 0.3333;
double sensorReading = 0.0;
//Perform the opeartion.
sensorReading = 1.0 / 3.0;
// Get the absolute floating point value and
// Check up to 4 digits.
if (fabs(sensorReading - targetValue) < 1E-4)
{
//Print equal if the values are close enough.
cout << "Equal" << endl;
}
else
{
//Print not equal if the values are not
//close enough.
cout << "Not equal" << endl;
}
system("pause");
//Return the value 0.
return 0;
}
