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podryga [215]
3 years ago
13

Write 12,430,000 in expanded form

Mathematics
2 answers:
poizon [28]3 years ago
5 0
10000000+2000000+400000+30000
Alisiya [41]3 years ago
3 0
10 000 000 2 000 000 400 000 30 000
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The table shows sets of ordered pads that form a relation
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(5,2) (-2,5) this is how you solve an equation using simple graphd

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2 years ago
If the two terms of a gemotric sequence are a1=216, and a2=72, which is the third term? a3?
Ierofanga [76]
GEOMETRIC \: \: PROGRESSIONS \\ \\ \\\\Let \: the \: G.P. \: be \: \: A \: , \: Ar \: , \: A {r}^{2} \: ... \\ \\ Where \:first \: term \: is \: \: A \: \: \\ and \: common \: ratio \: is \: \: R \\ \\ Let \: An \: denotes \: the \: \: nth \: term \: of \: \\ the \: given \: Geometric \: Progression \: \\ \\ It \: is \: given \: - \\ \\ A1 \: = \: 72 \\ \\ A2 \: = \: 216 \\ \\ Common \: ratio \: = \: \frac{A2}{A1} = \frac{216}{72} \\ \\ R = 3 \\ \\ A \: = \: 72 \\ \\ A3 \: = \: A {r}^{2} = 72 \times 3 \times 3 \\ \\ \\ Hence \: , \: A3 \: = \: 648 \: \: \: \: \: \: \: Ans.
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3 years ago
If I have 24 jolly ranchers and 64 starbursts what is the largest amount of bags I can fill? How many starbursts will be I’m eac
Rus_ich [418]

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Largest amount of bags that can be filled: 11

Starbursts in each bag: 3

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Find the greastest common factor between these two (which is 8) and divide the sum of the jolly ranchers and starbursts-which will be 88-by the greatest common factor. This will leave you with 11 bags that can be filled with 8 candies. To find the starbursts, divide 24 by 8 (3.)

5 0
2 years ago
Please someone help me
fomenos
Mmm looks like a test. I don't know if we should be answering this.
3 0
3 years ago
16. What is the area of the shaded region in terms of Tr? [20 points]
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= πr2
= π(5)2
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Area of the bigger circle inside
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Area of the smaller circle inside
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Area of shaded region
= 25π - 9π - 4π
= 12π square unit
6 0
2 years ago
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