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zhuklara [117]
3 years ago
5

Can you work out G and H for me please. preferably telling me how you did it aswell

Mathematics
1 answer:
Veronika [31]3 years ago
8 0
Abd is a right angled triangle so by pythagoras we know
{g}^{2}  =  {11}^{2}  +  {13}^{2}  \\  {g}^{2}  = 290 \\ g =  \sqrt{290}  \: or \: g = 17.03cm
and to calculate h we need to use the sine rule
\frac{h}{ \sin(22) }  =  \frac{g}{ \sin(32) }  \\  \frac{h}{ \sin(22) }  =  \frac{17.03}{ \sin(32) }  \\ h =  \frac{17.03}{ \sin(32) } \times  \sin(22)   \\ h = 12.04cm
i hope this helps
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Which of the following is a correct equation for the line passing through the point (-2,1) and having slope m= 1/2?
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Incomplete Question the complete Qs is

Which of the following is a correct equation for the line passing through the point (-2,1) and having slope m = 1/2?  

a: y=1/2x+2

b: y=-2x+1/2

c: x-2y=-4

d: y-1=1/2(x+2)

Answer:

The Correct option is c. x-2y=-4

Therefore the correct equation for the line passing through the point (-2,1) and having slope m= 1/2 is

x-2y=-4

Step-by-step explanation:

Given:

Slope = m =\dfrac{1}{2}

point A(x₁, y₁)=(-2,1)  

To Find:  

Equation of Line  =?  

Solution:  

Equation of a line passing through a points A( x₁ , y₁) and having slope m is given by the formula,  

i.e equation in point - slope form

(y-y_{1})=m(x-x_{1})

Now on substituting the slope and point A( x₁ , y₁) ≡ ( -2 , 1) we get

(y-1)=\dfrac{1}{2}(x-(-2))\\\\2y-2=x+2\\x-2y=-2-2=-4\\x-2y=-4 As required

Therefore the correct equation for the line passing through the point (-2,1) and having slope m= 1/2 is

x-2y=-4

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