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olganol [36]
4 years ago
15

The sun is about 93 x10 to the sixth power miles from earth. What is the distance written as a whole number

Mathematics
1 answer:
pantera1 [17]4 years ago
5 0
The answer to 93 x 10^6 = 93000000
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The snorkel costs $12 to rent.
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7 over 14 in its simplest form
eduard

Answer:

1/2

Step-by-step explanation:

Half of 14 is 7 therefore it is 1/2

3 0
4 years ago
Can anyone please help me with this?
madam [21]

Using difference of squares

a^{2} -b^{2} =(a-b)(a+b)

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3 years ago
Which value for x makes the sentence true? 1/50+x=1/10
nirvana33 [79]

Answer:

2/25 is the Answer, as a decimal it is 0.08

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

x + 1/50 = 1/10

Step 2: Subtract 1/50 from both sides.

x + 1/50 - 1/50 = 1/10 - 1/50

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Proof that it is the answer

0.02 + 0.08 = 0.1

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Hope this helps!

3 0
3 years ago
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CUMPLEIE
beks73 [17]

the magnitude of an earthquake that is 5,011 times more intense than a standard earthquake is 3.7

<u>Step-by-step explanation:</u>

Here we have , to find  the magnitude of an earthquake that is 5,011 times more intense than a standard earthquake . Let's find out:

We know that , Value of earthquake is given by formula

⇒ M = Log(\frac{I_1}{I_0} ) , Where M is magnitude of earthquake

I_1  is the measured magnitude of intensity of  earthquake .

I_0  is the standard magnitude of intensity of  earthquake .

According to question , I_1 = 5011I_0 , Hence

⇒ M = Log(\frac{I_1}{I_0} )

⇒ M = Log(\frac{5011(I_0)}{I_0} )

⇒ M = Log(5011 )

⇒ M =3.69924    { On rounding off we get }

⇒ M =3.7

Therefore , the magnitude of an earthquake that is 5,011 times more intense than a standard earthquake is 3.7

6 0
3 years ago
Read 2 more answers
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