Answer:
19.3 years
Step-by-step explanation:
Given that the initial mass of a sample of Element X is 100 grams,
The formula is given as:
N(t) = No × (1/2) ^t/t½
Element X is a radioactive isotope such that every 30 years, its mass decreases by half.
N(t) = Mass after time (t)
No = Initial mass = 100 grams
t½ = Half life = 30 grams
N(t) = 100 × (1/2) ^t/30
How long would it be until the mass of the sample reached 64 grams, to the nearest tenth of a year?
This means we are to find the time
N(t) = 100 × (1/2) ^t/30
N(t) = 64 grams
64 = 100(1/2)^t/30
Divide both sides by 100
64/100 = 100(1/2)^t/30/100
0.64 = (1/2)^t/30
Take the Log of both sides
log 0.64 = log (1/2)^t/30
log 0.64 = t/30(1/2)
t = 19.315685693242 years
Approximately = 19.3 years
Answer:-10/13
Step-by-step explanation:
3x+4 = (2/5)x + 2
First move the 4 to the other side by subtracting it.
it becomes : 3x = (2/5)x - 2
then multiply everything by 5 to get rid of the fraction.
it becomes 15x = 2x -10
then move the 2x to the other side by subtracting it.
you get 13x = -10
now you can divide everything by 13 to isolate the x.
and you get x = -10/13
Post this again so more people can see it cuz that’s what I do when no one answers my questions
A) 3y - x = 10 is the correct answer! (I just graphed it on Desmos.com)
