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Lady bird [3.3K]
3 years ago
6

A transversal intersects two lines which condition would make the two lines parallel

Mathematics
1 answer:
lys-0071 [83]3 years ago
3 0
The slope is that same
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What is the circumference of a circle with a diameter of 6 feet? Use 3.14 for pie.
stira [4]

Answer:

18.84

Step-by-step explanation:

7 0
3 years ago
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For a loan of $40,000 at 12% for 10 years, how much do you wind up paying back?
Masteriza [31]

Answer:

B . 4800

Step-by-step explanation:

12 percent of 40000 = 4800.

   

7 0
3 years ago
QUESTION 9
Mars2501 [29]

Answer:

x = 31

Step-by-step explanation:

Given:

f(x) =

2 {x}^{2}  - 1

g(x) = x + 2

We will first find g(2).

g(2) = 2 + 2 = 4

Next we will find f(g(2)).

f(g(2))= f(4) =

2( {4}^{2} ) - 1 \\  = 2(16) - 1 \\  = 32 - 1 \\  = 31

4 0
1 year ago
Use the factor theorem to determine whether or not the first polynomial is a factor of the second
krok68 [10]

Answer/Step-by-step explanation:

Based on the factor theorem, a polynomial, x - a, is said to be a factor of another polynomial, f(x), if an only if f(a) = 0.

Using this theorem, let's determine whether each of the given first polynomial, is a factor of the second polynomial.

1. x - 1; x² + 2x + 5

By the factor theorem, x - 1 will be a factor of f(x) = x² + 2x + 5, if and only if f(1) = 0.

f(1) = 1² + 2(1) + 5

= 1 + 2 + 5

= 8

Since f(1) ≠ 0, therefore the first polynomial, x - 1, is NOT a factor of the second polynomial, x² + 2x + 5.

2. x + 1; x³ - x - 2

By the factor theorem, x + 1 will be a factor of f(x) = x³ - x - 2, if and only if f(-1) = 0.

f(1) = -1³ - (-1) - 2

= -1 + 1 - 2

= -2

Since f(-1) ≠ 0, therefore the first polynomial, x + 1, is NOT a factor of the second polynomial, x³ - x - 2.

3. x - 4; 2x³ - 9x² + 9x - 20

By the factor theorem, x - 4 will be a factor of f(x) = 2x³ - 9x² + 9x - 20, if and only if f(4) = 0.

f(4) = 2(4)³ - 9(4)² + 9(4) - 20

= 128 - 144 + 36 - 20

= 0

Since f(4) = 0, therefore the first polynomial, x + 4, is a factor of the second polynomial, 2x³ - 9x² + 9x - 20.

4. a - 1; a³ - 2a² + a - 2

By the factor theorem, a - 1 will be a factor of f(a) = a³ - 2a² + a - 2, if and only if f(1) = 0.

f(1) = 1³ - 2(1)² + 1 - 2

= 1 - 2 + 1 - 2

= -2

Since f(1) ≠ 0, therefore the first polynomial, a - 1, is NOT a factor of the second polynomial, a³ - 2a² + a - 2.

5. y + 3; 2y³ + y² - 13y + 6

By the factor theorem, y + 3 will be a factor of f(y) = 2y³ + y² - 13y + 6, if and only if f(-3) = 0.

f(-3) = 2(-3)³ + (-3)² - 13(-3) + 6

= -54 + 9 + 39 + 6

= 0

Since f(-3) = 0, therefore the first polynomial, y + 3, is a factor of the second polynomial, 2y³ + y² - 13y + 6.

7 0
3 years ago
Can YOU plz help meh
Aleks [24]
8 × 20= 160; 8 × 4= 32; 160 + 32= 192; 8 × t= 192; 192 ÷ 8= 24; t=24
The answer is t = 24

Hope this helps :)
7 0
3 years ago
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