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Arada [10]
3 years ago
14

a box of rice cakes costs $1.95. What is the greatest number of boxes of rice cakes Jared can buy with $10?

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
5 0
The greatest number of boxes of rice cakes would be 5, because when you take $10 and divide it by how much every box would cost it would be 5.13. However, boxes are sold in wholes and you must round down to get the greatest whole number of boxes he can get, which would be 5 boxes of rice cakes.
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Answer:

a=4 and b = 0

Step-by-step explanation:

Given : \dfrac{\sqrt 3 -1}{\sqrt 3+1}+\dfrac{\sqrt 3+1}{\sqrt 3-1}=a+\sqrt 3 b

To find, The value of a and b

Solution,

Solving LHS of the given equation,

\dfrac{(\sqrt 3-1)^2+(\sqrt3+1)^2}{(\sqrt 3+1)(\sqrt 3-1)}=a+\sqrt 3 b

Since,

(a-b)^2=a^2+b^2-2ab\\\\(a+b)^2=a^2+b^2+2ab\\\\(a-b)(a+b)=a^2+b^2

So,

\dfrac{3+1-2\sqrt 3+3+1+2\sqrt 3}{3-1}=a+\sqrt 3 b\\\\4=a+\sqrt 3 b

or

4+0=a+\sqrt 3 b

On comparing we get :

a = 4 and b = 0

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