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alexandr402 [8]
3 years ago
14

To eliminate the terms and solve for y in the tewest steps, by which constants should the equations be multiplied by before

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
6 0

Answer:

the equation is not shown...

Step-by-step explanation:

but to solve for y you should use the first equation that is use the coefficient of x in the first equation to multiply all the terms in the second equation.

And use the coeffient of x in the second equation to multiply the the terms in the first equation.

It would have been better if the equation was shown for better explanation.

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What is the nineteenth term in the sequence 7, 10, 13, 16,...? A 64 B 61 C 57 D 19
Over [174]

Answer:

B. 61

Step-by-step explanation:

7, 10, 13, 16...

ok so were starting with 7 and adding 3 every time

im going to do 3 times 19 like as if we started with 3 then im going to add 4

3 x 19 = 57

57 + 4 = 61

the 19th term is 61

8 0
3 years ago
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The student council is planning the school carnival. Each ticket costs $2.50. Explain how to write an equation that represents t
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Step-by-step explanation:

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3 years ago
A vendor pays a rock band 1/3 of the total profit from T-shirts and sweatshirts sold at every concert. The vendor paid the rock
cluponka [151]
Let's call x = profit from the sweatshirt sales 1) A vendor pays to rock band 13% of the total profit from T-shirts and sweatshirts sold at every concert. 2) the profit from T-shirts sales was $ 1,632 3) The vendor paid the rock band $ 726 after the last concert We then have the following equation: 0.13 * (1632 + x) = 726 Clearing x: (1632 + x) = (726 / 0.13) x = (726 / 0.13) - 1632 = 3953 $ Answer: the profit from sweatshirt sales was 3953 $
5 0
3 years ago
In a library where the ratio of men to women is 1 to 1, of the total members are men.
masha68 [24]
The men are in equal amount to women if the ratio is 1:1
5 0
3 years ago
Find dy/dx of the function y = √x sec*-1 (√x)​
ELEN [110]

Hi there!

\large\boxed{\frac{dy}{dx} = \frac{1}{2\sqrt{x}}sec^{-1}(\sqrt{x}) +  \frac{1}{2|\sqrt{x}|\sqrt{{x} - 1}}}

y = \sqrt{x} * sec^{-1}(-\sqrt{x}})

Use the chain rule and multiplication rules to solve:

g(x) * f(x) = f'(x)g(x) + g'(x)f(x)

g(f(x)) = g'(f(x)) * 'f(x))

Thus:

f(x) = √x

g(x) = sec⁻¹ (√x)

\frac{dy}{dx} = \frac{1}{2\sqrt{x}}sec^{-1}(\sqrt{x}) + \sqrt{x} * \frac{1}{\sqrt{x}\sqrt{\sqrt{x}^{2} - 1}} * \frac{1}{2\sqrt{x}}

Simplify:

\frac{dy}{dx} = \frac{1}{2\sqrt{x}}sec^{-1}(\sqrt{x}) + \sqrt{x} * \frac{1}{2|x|\sqrt{{x} - 1}}

\frac{dy}{dx} = \frac{1}{2\sqrt{x}}sec^{-1}(\sqrt{x}) +  \frac{1}{2|\sqrt{x}|\sqrt{{x} - 1}}

5 0
3 years ago
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