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balu736 [363]
3 years ago
12

Chetan wants to make a necklace with 50 beads. He knows that 12 beads take up 5 inches of string but the store only sells string

by the centimeter. How many centimeters should he buy? Explain
Mathematics
2 answers:
Arada [10]3 years ago
5 0
1 inch = 2.54 cm
12 beads = 5 inches
50 beads = 20.833 inches
20.833 inches = 52.92 cm

about 53 cm needed for 50 beads
notka56 [123]3 years ago
5 0

Answer:

53 cm

Step-by-step explanation:

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mel-nik [20]

Answer:

I believe the answere is B

Step-by-step explanation:

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7 0
2 years ago
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Explain why (4, 1) is not a solution to the equation y=3x+1
nexus9112 [7]

In (4, 1) 4 represents x, and 1 represents y

y = 3x + 1

1 = 3(4)+1

1 = 12 + 1

1 ≠ 13   ← sides are not equal so (4, 1) is not a solution to y=3x+1

6 0
3 years ago
Find , , and if and terminates in quadrant .
ioda

sin2x =12/13

cos2x = 5/13

tan2x = 12/5

STEP - BY - STEP EXPLANATION

What to find?

• sin2x

,

• cos2x

,

• tan2x

Given:

tanx = 2/3 = opposite / adjacent

We need to first make a sketch of the given problem.

Let h be the hypotenuse.

We need to find sinx and cos x, but to find sinx and cosx, first determine the value of h.

Using the Pythagoras theorem;

hypotenuse² = opposite² + adjacent²

h² = 2² + 3²

h² = 4 + 9

h² =13

Take the square root of both-side of the equation.

h =√13

This implies that hypotenuse = √13

We can now proceed to find the values of ainx and cosx.

Using the trigonometric ratio;

\sin x=\frac{opposite}{\text{hypotenuse}}=\frac{2}{\sqrt[]{13}}\cos x=\frac{adjacent}{\text{hypotenuse}}=\frac{3}{\sqrt[]{13}}

And we know that tanx =2/3

From the trigonometric identity;

sin 2x = 2sinxcosx

Substitute the value of sinx , cosx and then simplify.

\sin 2x=2(\frac{2}{\sqrt[]{13}})(\frac{3}{\sqrt[]{13}})=\frac{12}{13}

Hence, sin2x = 12/13

cos2x = cos²x - sin²x

Substitute the value of cosx, sinx and simplify.

\begin{gathered} \cos 2x=(\frac{3}{\sqrt[]{13}})^2-(\frac{2}{\sqrt[]{13}})^2 \\  \\ =\frac{9}{13}-\frac{4}{13} \\ =\frac{5}{13} \end{gathered}

Hence, cos2x = 5/13

tan2x = 2tanx / 1- tan²x

\tan 2x=\frac{2\tan x}{1-\tan ^2x}=\frac{2(\frac{2}{3})}{1-(\frac{2}{3})^2}=\frac{\frac{4}{3}}{1-\frac{4}{9}}=\frac{\frac{4}{3}}{\frac{9-4}{9}}=\frac{\frac{4}{3}}{\frac{5}{9}}=\frac{4}{3}\times\frac{9}{5}=\frac{4}{1}\times\frac{3}{5}=\frac{12}{5}

OR

\tan 2x=\frac{\sin 2x}{\cos 2x}=\frac{\frac{12}{13}}{\frac{5}{13}}=\frac{12}{5}

Hence, tan2x = 12/5

Therefore,

sin2x =12/13

cos2x = 5/13

tan2x = 12/5

3 0
1 year ago
If r=10 and s=31 find R. Round to the nearest tenth
Vsevolod [243]

Answer: option c.

Step-by-step explanation:

You need to remember the identity:

tan\alpha=\frac{opposite}{adjacent}

The inverse of the tangent function is arctangent. You need to use this to calculate the angle "R":

 \alpha =arctan(\frac{opposite}{adjacent})

You know that you need to find the measure of "R" and r=10 (which is the opposite side) and s=31 (which is the adjacent side), you can sustitute values into \alpha =arctan(\frac{opposite}{adjacent})

Then, you get:

R=arctan(\frac{10}{31})\\\\R=17.9\°

3 0
3 years ago
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Which pair of triangles are congruent by ASA ?
Eddi Din [679]
Your answer is going to be letter D.)?
6 0
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