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4 years ago

45 km/have to m/s solution

1 answer:

7 0

We know, 1 m/s = 3.6 Km/h
So, 45 Km/h = 45/3.6 = 12.5 m/s

In short, It would be equal to 12.5 m/s

Hope this helps!

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Two coherent sources of radio waves, A and B, are 5.00 meters apart. Each source emits waves with wavelength 6.00 meters. Consid

kompoz [17]

a) 2.5 m

The condition for constructive interference to occur is

$|d_A-d_B|=m \lambda$ (1)

where

dA is the distance of the point from source A

dB is the distance of the point from source B

m is an integer number

$\lambda=6.0 m$ is the wavelength of the wave

We immediately notice that solutions to the equation are only possible if m=0: otherwise, the difference between dA and dB would be at least 6.0 m, which is impossible since the two sources have a separation of 5.0 m (and we are considering only points between the two sources). Therefore we have

$d_A - d_B = 0\\d_A = d_B = \frac{5.0 m}{2}=2.5 m$

So, constructive interference occurs halfway between the two sources.

b) 1 m, 4 m

The condition for destructive interference to occur is

$|d_A-d_B|=(m+\frac{1}{2}) \lambda$ (1)

As before, solutions are only possible for m=0, otherwise the point would not lie between the two sources.

So for m=0, we have:

$|d_A - d_B| = \frac{\lambda}{2} = 3$

So, the two possible solutions are (using $d_B = 5- d_A$ )

$d_A = d_B + 3 \\d_A = (5-d_A)+3\\2d_A = 5+3 = 8\\d=4$

and

$d_B - d_A = 3\\(5-d_A)-d_A=3\\5-2d_A = 3\\2d_A = 2\\d_A = 1$

So, the solutions are dA= 1 m and dA=4 m.

5 0

3 years ago

astronauts in space cannot weigh themselves by standing on a bathroom scale. Instead, they determine their mass by oscillating o

devlian [24]

Answer:

The right answer is:

(a) 63.83 kg

(b) 0.725 m/s

Explanation:

The given query seems to be incomplete. Below is the attachment of the full question is attached.

The given values are:

T = 3 sec

k = 280 N/m

(a)

The mass of the string will be:

⇒ $T=2 \pi\sqrt{\frac{m}{k} }$

or,

⇒ $m=\frac{k T^2}{4 \pi^2}$

On substituting the values, we get

⇒ $=\frac{280\times (3)^2}{4 \pi^2}$

⇒ $=\frac{280\times 9}{4\times (3.14)^2}$

⇒ $=68.83 \ kg$

(b)

The speed of the string will be:

⇒ $\frac{1}{2}k(0.4)^2=\frac{1}{2}k(0.2)^2+\frac{1}{2}mv^2$

then,

⇒ $v=\sqrt{\frac{k((0.4)^2-(0.2)^2)}{m} }$

On substituting the values, we get

⇒ $=\sqrt{\frac{280\times ((0.4)^2-(0.2)^2)}{63.83} }$

⇒ $=\sqrt{\frac{280(0.16-0.04)}{63.83} }$

⇒ $=\sqrt{\frac{280\times 0.12}{63.83} }$

⇒ $=0.725 \ m/s$

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3 years ago

How would you describe the relationship between the mass of a car and its kinetic energy? A) As the mass of a car increases, its

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answer is A

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4 years ago

When conducting this experiment, some procedures call for heating the substance several

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Answer:

when completing a science experiment it is important to run multiple tests do as to reduce the risk of any outliers of false results

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3 years ago

it is natural tendency of bodies to eventually come to a rest position .(true or false )physic question

DENIUS [597]

Answer:

True

Explanation:

Newton's first law of motion is applicable to both moving and nonmoving objects. ... It would take an unbalanced force to keep an object in motion at a constant velocity. False- balanced force. It is the natural tendency of all objects to eventually come to a rest position.

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3 years ago

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