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victus00 [196]
3 years ago
15

What should be the ending of the second element in a covalent compound?

Physics
1 answer:
Evgen [1.6K]3 years ago
8 0

Answer:

-ide

Explanation:

the second element is names by taking the stem of the element name and adding -ide. a system if numerical prefixes is used to specify the the number if atoms in a molecule.

You might be interested in
A proton moves perpendicular to a uniform magnetic field B with arrow at a speed of 2.40 107 m/s and experiences an acceleration
noname [10]

Answer:

0.00956770833 T

Explanation:

q = Charge of electron = 1.6\times 10^{-19}\ C

m = Mass of proton = 1.67\times 10^{-27}\ kg

a = Acceleration = 2.2\times 10^{13}\ m/s^2

v = Velocity = 2.4\times 10^{7}\ m/s

Magnetic field is given by

B=\dfrac{ma}{qv}\\\Rightarrow B=\dfrac{1.67\times 10^{-27}\times 2.2\times 10^{13}}{1.6\times 10^{-19}\times 2.4\times 10^{7}}\\\Rightarrow B=0.00956770833\ T

The magnetic field is 0.00956770833 T

4 0
3 years ago
Which statement is accurate about how the aurora borealis is formed?
g100num [7]

Answer:

When the electrons jump to a higher energy state, they release energy as electromagnetic radiation, light.

Explanation:

When the solar wind gets past the magnetic field and travels towards the Earth, it runs into the atmosphere. As the protons and electrons from the solar wind hit the particles in the Earth's atmosphere, they release energy – and this is what causes the northern lights.

7 0
3 years ago
How much mass does the sun lose through nuclear fusion per second?
Mekhanik [1.2K]

Answer:

1.10^6 kg of mass per second

Explanation:

All energy lost by the sun comes from nuclear fusion.

Sun loses energy at 2.5*10^{19}J per hour, that is 9*10^{22}J/s

To find the mass lost by the sun in liberation of energy you use the famous Einstein's equation:

E=mc^2\\\\m=\frac{E}{c^2}=\frac{9*10^{22}}{(3*10^{8}m/s)^2}=1*10^6kg

hence, the sun liberates 1.10^6 kg of mass per second

3 0
4 years ago
Mary applies a force of 73 N to push a box with an acceleration of 0.48 m/s^2. When she increases the pushing force to 84 N, the
nikklg [1K]

Answer: 68.75\ kg, 0.06

Explanation:

Mary applies a force of 73 N to create an acceleration of 0.48\ m/s^2

When She increases force to 84 N, it creates an acceleration of 0.64\ m/s^2

Friction opposes the motion of box

\Rightarrow 73-f=m\times 0.48\quad \ldots(i)\\\Rightarrow 84-f=m\times 0.64\quad \ldots(ii)

Subtract (i) from (ii)

\Rightarrow 11=m(0.64-0.48)\\\Rightarrow m=68.75\ kg

Therefore friction is

\Rightarrow f=73-68.75\times 0.48\\\Rightarrow f=73-33\\\Rightarrow f=40\ N

Here, friction is kinetic friction which is given by

\Rightarrow f=\mu_kmg\\\Rightarrow 40=\mu_k 68.75\times 9.8\\\Rightarrow \mu_k=0.061

5 0
3 years ago
CCDs are _____ format detectors, which detect photons with _____ efficiency. analog, high analog, low digital, high digital, low
mars1129 [50]
High digital and high are the answers.

hope this helps
7 0
3 years ago
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