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Mekhanik [1.2K]
3 years ago
14

An object has a mass of 50.0 g and a volume of 10.5 cm3. What is the object's density?

Physics
1 answer:
seraphim [82]3 years ago
4 0
Volume=mass/density

volume=455.6/19.3

volume=23.6 mL

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The angle of deflection shows the amount of electric force on each balloon. A greater force causes the balloon to deflect to a g
UNO [17]

Answer:

Hello the options to your question is missing attached below are the missing options

  • Electrical forces are symmetrical, The electric repulsion of the Balloons is equal because electric forces between two objects are always symmetrical
  • The electric forces are equal in this case because both balloons had the same amount of electric charge

Answer :

Electrical forces are symmetrical, The electric repulsion of the Balloons is equal because electric forces between two objects are always symmetrical

Explanation:

The Balloons have the same amount of force exerted on them, because Electrical forces are symmetrical, The electric repulsion of the Balloons is equal because electric forces between two objects are always symmetrical, therefore the two Balloons are deflected to the same angle

7 0
4 years ago
An electron and a proton are held on an x axis, with the electron at x = + 1.000 m and the proton at x = - 1.000 m. Part A How m
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PART A)

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V = \frac{kq_1}{r_1} + \frac{kq_2}{r_2}

here we have

q_1 = 1.6 \times 10^{-19} C

q_2 = -1.6 \times 10^{-19} C

r_1 = r_2 = 1 m

now we have

V = \frac{Ke}{r} - \frac{Ke}{r}

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Now work done to move another charge from infinite to origin is given by

W = q(V_f - V_i)

here we will have

W = e(0 - 0) = 0

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PART B)

Initial potential energy of electron

U = \frac{Kq_1e}{r_1} + \frac{kq_2e}{r_2}

U = \frac{9\times 10^9(-1.6\times 10^{-19}(-1.6 \times 10^{-19})}{19} + \frac{9\times 10^9(1.6\times 10^{-19}(-1.6 \times 10^{-19})}{21}

U = (2.3\times 10^{-28})(\frac{1}{19} - \frac{1}{21})

U = 1.15\times 10^{-30}

Now we know

KE = \frac{1}{2}mv^2

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now by energy conservation we will have

So here initial total energy is sufficient high to reach the origin

PART C)

It will reach the origin

4 0
3 years ago
How is voltmeter connected in the circuit to measure the potential difference between two points?
34kurt

Voltmeter is used to find the potential difference between two points.

We always connect it in parallel to the points where we need the potential difference.

Here in order to make the reading accurate we can increase the resistance of voltmeter so that it can not withdraw any current from the circuit.

7 0
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Hypothetically speaking, if an object were located at the center of the Earth, the gravitational force on that object due to the
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Answer:

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Explanation:

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Answer:

sample. rewrite in your own words if you'd like.

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