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Mekhanik [1.2K]
3 years ago
14

An object has a mass of 50.0 g and a volume of 10.5 cm3. What is the object's density?

Physics
1 answer:
seraphim [82]3 years ago
4 0
Volume=mass/density

volume=455.6/19.3

volume=23.6 mL

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Uses of Photodiode.State the 8 uses of phototide...................​
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A block of mass m rests on a frictionless, horizontal surface. A cord attached to the block passes over a pulley whose radius is
ra1l [238]

Answer:

Explanation:

Let the tension in the cord be T₁ and T₂  .

for motion of block placed on horizontal table

T₁ = m a  , a is acceleration of the whole system .

for motion of hanging bucket of mass m

mg - T₂ = ma

adding the two equation

mg + T₁- T₂ = 2ma

for rotational motion of the pulley

torque = moment of inertia x angular acceleration

(T₂ - T₁) R = I x α , I is moment of inertia of pulley , α is angular acceleration .

(mg - 2ma ) R = I x α

(mg - 2ma ) R = I x a / R

(mg - 2ma ) R² = I x a

mgR² =  2ma R² + I x a

a = mgR² / (2m R² + I )

Since body moves by distance d in time T

d = 1/2 a T²

a = 2d / T²

mgR² / (2m R² + I ) = 2d / T²

mgR²T² = 2d x (2m R² + I )

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I =  m R² ( gT² - 4d ) ] / 2d .

3 0
4 years ago
Scientist who discovered that the nucleus contains neutrons in addition to protons.
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Answer: James Chadwick

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Any change in the speed or direction of an object is called<br> ?
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5 0
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Read 2 more answers
A wildlife photographer uses a moderate telephoto lens of focal length 135 mm and maximum aperture f/4.00 to photograph a bear t
labwork [276]

Answer:

<h3>(A) The width x = 0.24 \times 10^{-3} m</h3><h3>(B) The new width is 1.32 \times 10^{-3} m</h3>

Explanation:

Given :

Focal length f =   135 \times 10^{-3}  m

Maximum aperture D = \frac{f}{4}

Wavelength \lambda = 550 \times 10^{-9} m

(A)

From rayleigh criterion,

  \theta = \frac{1.22 \lambda }{D}

  \theta =\frac{ 1.22 \times 550 \times 10^{-9}  }{33.75 \times 10^{-3} }

  \theta = 1.98 \times 10^{-5} rad

From angle formula,

  x = R\theta

Where R = 12 m ( given in example )

x = 12 \times 1.98 \times 10^{-5} m

x = 23.76 \times 10^{-5}

x = 0.24 \times 10^{-3} m

(B)

We know that \theta is proportional to the x and inversely proportional to the D

so we write the new width, here x is 5.5 times larger than above case

   x = 0.24 \times  10^{-3}  \times \frac{22}{4}

   x = 1.32 \times 10^{-3} m

6 0
3 years ago
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