Answer:
the speed of the bullet before striking the block is 302.3 m/s.
Explanation:
Given;
mass of the bullet, m₁ = 28.3 g = 0.0283 kg
mass of the wooden block, m₂ = 5004 g = 5.004 kg
initial velocity of the block, u₂ = 0
final velocity of the bullet-wood system, v = 1.7 m/s
let the initial velocity of the bullet before striking the block = u₁
Apply the principle of conservation of linear momentum to determine the initial velocity of the bullet.
m₁u₁ + m₂u₂ = v(m₁ + m₂)
0.0283u₁ + 5.004 x 0 = 1.7(0.0283 + 5.004)
0.0283u₁ = 8.5549
u₁ = 8.5549 / 0.0283
u₁ = 302.3 m/s
Therefore, the speed of the bullet before striking the block is 302.3 m/s.
Answer:
3 m/s²
Explanation:
Sum of forces in the x direction:
∑F = ma
68 N − 23 N = (15 kg) a
a = 3 m/s²
Answer:
The refractive index of the outer coating is 1.52.
Explanation:
Refractive index of interior part, n' = 1.97
critical angle, C = 50.4°
Let the refractive index of the coating is n.
Use the Snell's law,
Greetings!
<span>Six-year-old Fabian likes to fix things with his Dad around the house. He grabs his toy tools and sometimes even picks up a real screwdriver to try and help Dad fix whatever is broken. This is best explained by social learning theory.
The Social Learning theory is a theory of which young children start to learn to do more adult-like things.
Hope this helps!</span>