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kondor19780726 [428]
3 years ago
14

What is -4√12+√75 in the simplest radical form?

Mathematics
1 answer:
nekit [7.7K]3 years ago
3 0

Answer: -3\sqrt{3}

Step-by-step explanation:

-4\sqrt{12} + \sqrt{75}

\sqrt{12} can be written as \sqrt{4} x \sqrt{3}

which is the same as 2\sqrt{3}

Also , \sqrt{75} can be written as \sqrt{25} x\sqrt{3} , which is the same as 5\sqrt{3}

Substituting into the main question , we have

-4 (2\sqrt{3} ) + 5\sqrt{3}

= -8\sqrt{3} + 5\sqrt{3}

= -3\sqrt{3}

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Answer:

Ayush's route is 0.7 km or 700m longer than Sumit route.

Step-by-step explanation:

Ayush's route is 1km 2hm long while sumit route is 2hm 30dam.

We know that,

1 km = 10 hm

1 dam = 0.1 hm

Using these conversions we get

Ayush's route = 1km 2hm = (1×10) hm + 2 hm = 12 hm

Sumit route = 2hm 30dam = 2 hm + (30×0.1) hm = 2 hm + 3 hm = 5 hm

Ayush's route is longer.

Difference = 12 hm - 5 hm = 7 hm = 0.7 km            [1 km = 10 hm]

Hence, Ayush's route is 0.7 km or 700 m longer than Sumit route.

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