Answer:
Mercury
Explanation:
While it is true that most metals are solid at room temperature, mercury is liquid at room temperature hence mercury is often designated as the 'liquid metal'.
Thus, if i find a bottle on the shelf that has no solid in it, only liquid and i know that only pure metals are stored in that area of the laboratory, then i will quickly relabel it as mercury.
X:5.8g=16:(23+1+12+3*16)
x:5.=16:84
x:=5.8* 16/84
this is approximately 1.1
<u>Answer:</u>
<u>For a:</u> The volume of the box is 217.5 mL
<u>For b:</u> The volume of the box is 0.2175 L
<u>Explanation:</u>
The box is a type of cuboid.
To calculate the volume of cuboid, we use the equation:
where,
V = volume of cuboid
l = length of cuboid = 10.00 cm
b = breadth of cuboid = 7.25 cm
h = height of cuboid = 3.00 cm
Putting values in above equation, we get:
To convert the volume of cuboid into milliliters, we use the conversion factor:
So,
Hence, the volume of the box is 217.5 mL
To convert the volume of cuboid into liters, we use the conversion factor:
So,
Hence, the volume of the box is 0.2175 L
Answer is: an oxybromate compound is KBrO₄ (x = 4).
ω(Br) = 43.66% ÷ 100%.
ω(Br) = 0.4366; mass percentage of bromine.
If we take 100 grams of compound:
m(Br) = ω(Br) · 100 g.
m(Br) = 0.4366 · 100 g.
m(Br) = 43.66 g; mass of bromine.
n(Br) = m(Br) ÷ M(Br).
n(Br) = 43.66 g ÷ 79.9 g/mol,
n(Br) = 0.55 mol; amoun of bromine.
From chemical formula (KBrOₓ), amount of potassium is equal to amount of bromine: n(Br) = n(K).
m(K) = 0.55 mol · 39.1 g/mol.
m(K) = 21.365 g; mass of potassium in the compound.
m(O) = 100 g - 21.365 g - 43.66 g.
m(O) =34.97 g; mass of oxygen.
n(O) = 34.97 g ÷ 16 g/mol.
n(O) = 2.185 mol.
n(K) : n(Br) : n(O) = 0.55 mol : 0.55 mol : 2.185 mol /÷ 0.55 mol.
n(K) : n(Br) : n(O) = 1 : 1 : 4.
I think it is Global warming
