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wlad13 [49]
2 years ago
5

The blackbody curve for a star named beta is shown below. The most intense radiation for this star occurs in what spectral band?

Chemistry
2 answers:
Viefleur [7K]2 years ago
5 0
The answer is Infrared.
elena-s [515]2 years ago
4 0

Answer: Ultraviolet

Explanation:

The Electromagnetic spectrum involves gamma rays , X rays, ultra violet rays, visible rays, infrared rays, micro waves and radio waves which are arranged in order of increasing wavelength and decreasing frequency.

The wavelength range for gamma rays is less than 0.001 nm.

The wavelength range for ultraviolet rays is 1 nm to 400 nm.

The wavelength range for visible rays is 400 nm to 750 nm.

The wavelength range for infra red rays is 700 nm to 1000000 nm.

It can be seen from the graph that the most intense radiation for the star occurs near a wavelength of 200 nm , thus the most intense radiation occurs in ultraviolet band.

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Answer:

electrical

Explanation:

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7 0
3 years ago
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The ksp of calcium carbonate, caco3, is 3.36 × 10-9 m2. calculate the solubility of this compound in g/l.
maw [93]
CaCO₃ partially dissociates in water as Ca²⁺ and CO₃²⁻. The balanced equation is,
                       CaCO₃(s) ⇄ Ca²⁺(aq) + CO₃²⁻(aq)
Initial                Y                   -                 -
Change           -X                  +X              +X
Equilibrium      Y-X                 X                X

Ksp for the CaCO₃(s) is 3.36 x 10⁻⁹ M²

                Ksp = [Ca²⁺(aq)][CO₃²⁻(aq)]
3.36 x 10⁻⁹ M² = X * X
3.36 x 10⁻⁹ M² = X²
                    X = 5.79 x 10⁻⁵ M

Hence the solubility of CaCO₃(s) = 5.79 x 10⁻⁵ M
                                                     = 5.79 x 10⁻⁵ mol/L

Molar mass of CaCO₃ = 100 g mol⁻¹

Hence the solubility of CaCO₃ = 5.79 x 10⁻⁵ mol/L x 100 g mol⁻¹
                                                 = 5.79 x 10⁻³ g/L

7 0
3 years ago
A sample of a compound contains 60.0 g C and 5.05 g H. Its molar mass is 78.12 g/mol. What is the compound’s molecular formula?
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A sample of a compound contains 60.0 g C and 5.05 g H.

divide by molar mass of C(12) and H(1) to get molar ratio

C: 60/12=5 and H: 5/1=5

so C:H=5:5=1:1

total molar mass=78

divide by 1C+1H to find the formula: 78/(12+1)=78/13=6

compound is C6H6


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