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wlad13 [49]
2 years ago
5

The blackbody curve for a star named beta is shown below. The most intense radiation for this star occurs in what spectral band?

Chemistry
2 answers:
Viefleur [7K]2 years ago
5 0
The answer is Infrared.
elena-s [515]2 years ago
4 0

Answer: Ultraviolet

Explanation:

The Electromagnetic spectrum involves gamma rays , X rays, ultra violet rays, visible rays, infrared rays, micro waves and radio waves which are arranged in order of increasing wavelength and decreasing frequency.

The wavelength range for gamma rays is less than 0.001 nm.

The wavelength range for ultraviolet rays is 1 nm to 400 nm.

The wavelength range for visible rays is 400 nm to 750 nm.

The wavelength range for infra red rays is 700 nm to 1000000 nm.

It can be seen from the graph that the most intense radiation for the star occurs near a wavelength of 200 nm , thus the most intense radiation occurs in ultraviolet band.

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. How many moles of ammonia gas, NH3, are required to fill a volume of 50 liters at STP?
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Elements occur in a number of isotopic forms. In this problem, you will learn about the notation used to distinguish different i
alina1380 [7]

Answer:

  • <em>Number of protons, Z = 14</em>
  • <em>Number of neutrons, N = 14</em>

Explanation:

<u>1) About isotopes:</u>

<em>Isotopes</em> are different kind of atoms of the same element. Hence, they have the atomic number (Z), which is the number of <em>protons</em>, the same number of electrons (talking about to neutral atoms, not ions), and different <em>number of neutrons N).</em>

This is, it is the number of neutrons what distinguish different isotopes of an element.

<u>2) About the notation used to distinguish different isotopes:</u>

A superscript and a subscript, both to the left of the chemical symbol of the element, are used to <em>distinguish different isotopes</em>:

       A ←------------- This superscript tells the mass number of the isotope

           X ←--------- This is the chemical symbol of the element

      Z ←-------------- This subscript is the atomic number of isotope

In our case, the notiation for the isotope of silicon is:  ²⁸₁₄ Si

So, we have:

  • 28 is the mass number (A)
  • 14 is the atomic number (Z)
  • Si is the chemical symbol.

Now, you can answer the questions of the <em>part A</em>:

  • Number of protons: Z = 14
  • Number of neutrons N:

       mass number = number of protons + number of neutrons

                   A         =                 Z              +                N

⇒ N = A - Z = 28 - 14 = 14

In <u>conclusion</u>:

  • Number of protons, Z = 14
  • Number of neutrons, N = 14
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A compound is 7.74% hydrogen and 92.26% carbon by mass. At 100°C a 0.6883 g sample of the gas occupies 250 mL when the pressure
ycow [4]

<u>Answer:</u> The molecular formula for the compound is C_6H_6

<u>Explanation:</u>

We are given:

Percentage of C = 92.26 %

Percentage of H = 7.74 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 92.26 g

Mass of H = 7.74 g

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{92.26g}{12g/mole}=7.68moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{7.74g}{1g/mole}=7.74moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 7.68 moles.

For Carbon = \frac{7.68}{7.68}=1

For Hydrogen = \frac{7.74}{7.68}=1

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H = 1 : 1

The empirical formula for the given compound is CH

  • <u>Calculating the molar mass of the compound:</u>

To calculate the molecular mass, we use the equation given by ideal gas equation:

PV = nRT

Or,

PV=\frac{m}{M}RT

where,

P = pressure of the gas = 820 torr

V = Volume of gas = 250 mL = 0.250 L  (Conversion factor:  1 L = 1000 mL )

m = mass of gas = 0.6883 g

M = Molar mass of gas = ?

R = Gas constant = 62.3637\text{ L. torr }mol^{-1}K^{-1}

T = temperature of the gas = 100^oC=(100+273)K=373K

Putting values in above equation, we get:

820torr\times 0.250L=\frac{0.6883g}{M}\times 62.3637\text{ L torr }mol^{-1}K^{-1}\times 373K\\\\M=\frac{0.6883\times 62.3637\times 373}{820\times 0.250}=78.10g/mol

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

n=\frac{\text{Molecular mass}}{\text{Empirical mass}}

We are given:

Mass of molecular formula = 78.10 g/mol

Mass of empirical formula = 13 g/mol

Putting values in above equation, we get:

n=\frac{78.10g/mol}{13g/mol}=6

Multiplying this valency by the subscript of every element of empirical formula, we get:

C_{(1\times 6)}H_{(1\times 6)}=C_6H_6

Hence, the molecular formula for the compound is C_6H_6

8 0
3 years ago
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