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Oduvanchick [21]
3 years ago
7

You are a chemist working in your laboratory. In your storage closet you have a cabinet that holds only samples of pure elements

, no compounds. While looking for a sample of lithium (Li), you notice that the label on one bottle has worn off. The room is at normal temperature. The contents of the bottle are liquid and do not look metallic. What element should you relabel the bottle as?
Chemistry
1 answer:
Vladimir79 [104]3 years ago
7 0

Answer:

Mercury

Explanation:

While it is true that most metals are solid at room temperature, mercury is liquid at room temperature hence mercury is often designated as the 'liquid metal'.

Thus, if i find a bottle on the shelf that has no solid in it, only liquid and i know that only pure metals are stored in that area of the laboratory, then i will quickly relabel it as mercury.

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how many moles of an ideal gas would occupy a 25.0 liter container when the temperature is 295 K and the pressure is 0.850 atm?
BlackZzzverrR [31]

Answer:

Required number of moles of ideal gas is 0.877 moles.

Explanation:

Pressure (P) = 0.850 atm

Temperature (T) = 295 K

Volume (V) = 25 ltr

Universal gas constant (R) = 0.0821

no of moles (n) = ?

we have the ideal gas equation as:

                           PV= nRT

                or, 0.850× 25 = n × 0.0821 × 295

                or, n = 0.877 moles

Hence the required number of moles of an ideal gas is 0.877 moles.

8 0
3 years ago
How many moles of HCl would react with 37.1 mL of 0.138 M Sr(OH)2
Lena [83]

Answer is: 0.102 moles of HCl would react.

Balanced chemical reaction:

2HCl(aq) + Sr(OH)₂ → SrCl₂(aq) + 2H₂O(l).

V(Sr(OH)₂) = 37.1 mL ÷ 1000 mL/L.

V(Sr(OH)₂) = 0.0371 L; volume of the strontium hydroxide solution.

c(Sr(OH)₂) = 0.138 M; molarity of the strontium hydroxide solution.

n(Sr(OH)₂) = c(Sr(OH)₂) · V(Sr(OH)₂).

n(Sr(OH)₂) = 0.0371 L · 0.138 mol/L.

n(Sr(OH)₂) = 0.0051 mol; amount of the strontium hydroxide.

From balanced chemical reaction: n(Sr(OH)₂) : n(HCl) = 1 : 2.

n(HCl) = 2 · n(Sr(OH)₂).

n(HCl) = 2 · 0.0051 mol.

n(HCl) = 0.0102 mol; amount of the hydrochloric acid.

5 0
3 years ago
Is this the correct procedure for cleaning volumetric glassware prior to making a measurement: first, rinse with tap water. Seco
Bogdan [553]

The steps to be followed while cleaning volumetric glassware are:

1. Remnants from the previous measurements are wiped off with the help of paper towel.

2. The glassware is then soaked overnight in warm soap solution.

3. Then before rinsing with tap water, the glassware are scrubbed with an appropriate brush.

4. After scrubbing, the glassware is rinsed thoroughly with tap water in order to make sure there are no traces of soap solution.

5. The glassware is then rinsed with de-ionized water and finally with the solution that would be used for the volumetric measurement.

6 0
3 years ago
Read 2 more answers
Could someone help me with this? No links, will give brainliest.
Ganezh [65]

Answer: I think it represents the SiO

Explanation:

6 0
3 years ago
When 1.95 g of co(no3)2 is dissolved in 0.350 l of 0.220 m koh, what are [ co2+], [ co(oh)42−], and [ oh−] if kf of co(oh)42− =
Airida [17]
Mass of Co(NO₃)₂ = 1.95 g
V KOH = 0.350 L
[KOH] = 0.220 M
Kf = 5.0 x 10⁹
molar mass of Co(NO₃)₂ = 182.943 g/mol
so [Co(NO₃)₂] = 1.95 / (0.350 * 182.943) = 0.03045 M
[Co²⁺] = 0.03045 M
[OH⁻] = 0.22 M
chemical reaction:
             Co²⁺(aq) + 4 OH⁻    ⇄      Co(OH)₄²⁻
I (M)      0.03045      0.22                   0
C (M)   - 0.03045   - 4 (0.03045)      0.03045
E (M)       - x         0.22 - 4(0.03045)   0.03045
                              = 0.0982
Kf  = [Co(OH)₄²⁻] / [Co⁺²][OH⁻]⁴
5.0 x 10⁹ = (0.03045) / x (0.0982)⁴
x = 6.5489 x 10⁻⁸
at equilibrium:
[Co²⁺] = 6.54 x 10⁻⁸
[OH⁻] = 0.0982 M
[Co(OH)₄²⁻] = 0.03045 M



4 0
3 years ago
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