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____ [38]
3 years ago
8

What graph represents the piecewise-defined function?

Mathematics
1 answer:
ale4655 [162]3 years ago
6 0

AnswerStep-by-step explanation: 54

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babunello [35]

If the functions are inverses, then f(g(x)) = x.

A.

\displaystyle f(g(x))=f\left(\frac{3x+1}{3}\right)=\frac{1}{\frac{3x+1}{x}-3}\\\\=\frac{1}{\left(\frac{3x+1-3x}{x}\right)}=\frac{1}{\left(\frac{1}{x}\right)}=x

The functions are inverses of each other.

B. The domain of f(x) = x≠3. The domain of g(x) is x≠0.

The domain of f(g(x)) is (-∞, 0) ∪ (0, ∞).

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4 0
3 years ago
a. Verify that the given point lies on the curve. b. Determine an equation of the line tangent to the curve at the given point.
xxMikexx [17]

Answer:

y = 13*( -x/9 + 1/5)

Step-by-step explanation:

Given:

- The curve has an equation as follows:

                               44 = 5x^2 + 3xy + 3y^2

Find:

a. Verify that the given point (2​,2​) lies on the curve.

b. Determine an equation of the line tangent to the curve at the given point.

Solution:

- To verify whether the point lies on the given curve we will substitute the coordinates of the point into the equation as follows:

                              44 = 5*(2)^2 + 3*(2)(2) + 3*(2)^2

                              44 = 20 + 12 + 12

                              44 = 44 ......Hence proven.

- The equation of the line tangent to the curve is expressed as a linear function as follows:

                              y = m*x + C

Where, m is the gradient of the line.

            C is the y-intercept.

                              m = Δy / Δx = dy/dx

- We will take the derivative of the given curve with respect to x as follows:

                             0 = 10x + 3*( y + xy' )  + 6y*y'\\\\-10x - 3y = y' ( 3x + 6y)\\\\ y' = - \frac{10x + 3y}{3x + 6y}

- Evaluate y' at the point (2,2) we get:

                            y' = - ( 10(2) + 3(2) ) / ( 3(2) + 6(2) )

                            y' = - ( 26 ) / (18)

                            y'= m = - 13/9

- To evaluate C, we will use the point (2,2) for linear expression above with m as follows:

                            y = -13*x/9 + C

                            2 =-13*(2)/9 + C

                            C = 13 / 5

- The equation of the tangent is as follows:

                            y = 13*( -x/9 + 1/5)  

8 0
3 years ago
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