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FromTheMoon [43]
3 years ago
9

The vertex of the parabola below is at the point (3, 2), and the point (4, 6) is on the parabola. what is the equation of the pa

rabola?
Mathematics
1 answer:
aliya0001 [1]3 years ago
4 0
 <span>Vertex (3, 2): 

h = 3 
k = 2 


Point (4, 6): 

x = 4 
y = 6 


Vertex Form: 

y = a(x - h)² + k 


Subbing known values, 

6 = a(4 - 3)² + 2 
6 = a(1)² + 2 
6 = a + 2 
a = 6 - 2 
a = 4 


Equation: 

y = 4(x - 3)² + 2</span>
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A particle moves according to a law of motion s = f(t), t ? 0, where t is measured in seconds and s in feet.
Usimov [2.4K]

Answer:

a) \frac{ds}{dt}= v(t) = 3t^2 -18t +15

b) v(t=3) = 3(3)^2 -18(3) +15=-12

c) t =1s, t=5s

d)  [0,1) \cup (5,\infty)

e) D = [1 -9 +15] +[(5^3 -9* (5^2)+ 15*5)-(1-9+15)]+ [(6^3 -9(6)^2 +15*6)-(5^3 -9(5)^2 +15*5)] =7+ |32|+7 =46

And we take the absolute value on the middle integral because the distance can't be negative.

f) a(t) = \frac{dv}{dt}= 6t -18

g) The particle is speeding up (1,3) \cup (5,\infty)

And would be slowing down from [0,1) \cup (3,5)

Step-by-step explanation:

For this case we have the following function given:

f(t) = s = t^3 -9t^2 +15 t

Part a: Find the velocity at time t.

For this case we just need to take the derivate of the position function respect to t like this:

\frac{ds}{dt}= v(t) = 3t^2 -18t +15

Part b: What is the velocity after 3 s?

For this case we just need to replace t=3 s into the velocity equation and we got:

v(t=3) = 3(3)^2 -18(3) +15=-12

Part c: When is the particle at rest?

The particle would be at rest when the velocity would be 0 so we need to solve the following equation:

3t^2 -18 t +15 =0

We can divide both sides of the equation by 3 and we got:

t^2 -6t +5=0

And if we factorize we need to find two numbers that added gives -6 and multiplied 5, so we got:

(t-5)*(t-1) =0

And for this case we got t =1s, t=5s

Part d: When is the particle moving in the positive direction? (Enter your answer in interval notation.)

For this case the particle is moving in the positive direction when the velocity is higher than 0:

t^2 -6t +5 >0

(t-5) *(t-1)>0

So then the intervals positive are [0,1) \cup (5,\infty)

Part e: Find the total distance traveled during the first 6 s.

We can calculate the total distance with the following integral:

D= \int_{0}^1 3t^2 -18t +15 dt + |\int_{1}^5 3t^2 -18t +15 dt| +\int_{5}^6 3t^2 -18t +15 dt= t^3 -9t^2 +15 t \Big|_0^1 + t^3 -9t^2 +15 t \Big|_1^5 + t^3 -9t^2 +15 t \Big|_5^6

And if we replace we got:

D = [1 -9 +15] +[(5^3 -9* (5^2)+ 15*5)-(1-9+15)]+ [(6^3 -9(6)^2 +15*6)-(5^3 -9(5)^2 +15*5)] =7+ |32|+7 =46

And we take the absolute value on the middle integral because the distance can't be negative.

Part f: Find the acceleration at time t.

For this case we ust need to take the derivate of the velocity respect to the time like this:

a(t) = \frac{dv}{dt}= 6t -18

Part g and h

The particle is speeding up (1,3) \cup (5,\infty)

And would be slowing down from [0,1) \cup (3,5)

5 0
3 years ago
One number is eight less than another. The sum of the numbers is 24
velikii [3]

Answer:

32

Step-by-step explanation:

a-8=24

clt

a=24+8

a=32

7 0
2 years ago
F(x )=x square +6x + 5 what is the x intercept to graph f(x)
siniylev [52]

Answer:

(-5, 0)

(-1, 0)

Step-by-step explanation:

x-intercepts are points where the graph intersects the x-axis (or when y = 0)

Step 1: Write out function

f(x) = x² + 6x + 5

Step 2: Factor

f(x) = (x + 5)(x + 1)

Step 3: Find binomial roots

x + 5 = 0

x = -5

x + 1 = 0

x = -1

Alternatively, you can graph the function and analyze the graph for x-intercepts:

6 0
3 years ago
A fair coin is tossed and a single number cube is rolled. the probability of rolling a number less than 5 is ________________. t
Alik [6]
You have a 4/ 6 chance 
then you have a 2/6 chance if the number is an odd number then reducing you would get 
1.   2/3 
2.  1/3 
7 0
3 years ago
Solve the system by substitution.<br> y = 3x + 14<br> y = X
lys-0071 [83]

Answer:

\boxed{x = -7~~and~~ y =-7}

Step-by-step explanation:

y = 3x + 14

y = x

.

x = 3x + 14

3x - x = -14

2x = -14

x = \frac{-14}{2}

x = -7

.

y = x

y = -7

4 0
3 years ago
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