1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
IgorLugansk [536]
3 years ago
6

A survey with a two-point scale was conducted in an organization. It concluded that 85% of the respondents were unsatisfied with

the career guidance they were provided. If 2,000 people participated in the survey,how many
people were satisfied with the career guidance.
Mathematics
2 answers:
Morgarella [4.7K]3 years ago
5 0

Answer:

Number of the peoples were satisfied with the career guidance are 300 .

Step-by-step explanation:

Formula

Percentage = \frac{Part\ value\times 100}{Total\ value}

As given

A survey with a two-point scale was conducted in an organization.

It concluded that 85% of the respondents were unsatisfied with the career guidance they were provided.

If 2,000 people participated in the survey.

Total value = 2000

Percentage = 85%

Putting all the values in the formula

85 = \frac{Part\ value\times 100}{2000}

Part\ value= \frac{2000\times 85}{100}

Part\ value= \frac{170000}{100}

Part value = 1700

i.e

People not satisfied by the career guidance = 1700

People satisfied by the career guidance = Total people participated in survey  - People not satisfied by the career guidance .

Putting the values in the above

                                                                  = 2000 - 1700

                                                                  = 300

Therefore the number of the peoples were satisfied with the career guidance are 300 .


Lubov Fominskaja [6]3 years ago
5 0
85% of 2000 is 1700, so 300 people were actually satisfied.:)
You might be interested in
If 40% of a given number is 8, then what is 15% of the given number?
Norma-Jean [14]
40% of a given number is 8...
0.40x = 8
x = 8 / 0.40
x = 20....so 20 is the given number

what is 15% of 20...
0.15(20) = 3 <==== ur answer
5 0
3 years ago
Percentage of words starting with T
Mkey [24]
Do what the hint says lol
4 0
2 years ago
Solve for x round to the nearest tenth. Show steps!
Dvinal [7]

Answer:

\large\boxed{x\approx56.44}

\large\text{It's close to 55.0}

Step-by-step explanation:

\tan12^o\approx0.2126\\\\\tan12^o=\dfrac{12}{x}\to\dfrac{12}{x}=0.2126\qquad\text{convert the decimal to the fraction}\\\\\dfrac{12}{x}=\dfrac{2126}{10000}\qquad\text{cross multiply}\\\\2126x=120000\qquad\text{divide both sides by 2126}\\\\x=\dfrac{120000}{2126}\\\\x\approx56.44

8 0
3 years ago
Select all statements that show correct reasoning for finding 15 = 3
mario62 [17]

Answer:

. Multiply 15 by 1, then divide by 5

6 0
2 years ago
Read 2 more answers
Beth has $108.50 in her bank account. She buys x shirts for $5.50 each. Write and solve an equation Beth can use to find how man
suter [353]
x-\ number\ of\ shirts\\\\&#10;x*5.50=108.50\ \ \ | divide\ by\ 5.50\\\\&#10;x\approx19\\\\&#10;She\ can\ buy\ 19\ shirts.
3 0
3 years ago
Read 2 more answers
Other questions:
  • PLEASE HELP QUICKLY 20 POINTS!!!
    7·2 answers
  • Use Newton's method to approximate the roots<br> of f(x) = 3x3 – 4x2 + 1 to six digits.
    5·1 answer
  • What are equivalent to 2:9
    5·1 answer
  • sally is y years old mike is the difference between 20 and Sally's age Joe is four years less than triple Sally's age
    15·1 answer
  • Julio Ernesto earns $15 an hour at his part-time job. Last week he worked 26 hours, and 45 minutes.. What was his gross pay for
    15·1 answer
  • What is the solution to the equation: 37x=9x+4
    13·2 answers
  • 1. What is the measure of arc QR? *<br><br> (check screenshot)
    9·1 answer
  • <img src="https://tex.z-dn.net/?f=%20%20%7Ba%7D%5E%7B2%7D%20%20%7Ba%7D%5E%7B4%7D%20%7Ba%7D%5E%7B5%7D%20answer%20%5C%3A%20a40%20%
    14·1 answer
  • Help me plzzzzzzzzzzzz
    12·1 answer
  • 1. The teacher assigns homework after 7/10
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!