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maw [93]
2 years ago
8

1. Find the area: 26 cm 39 cmI need help​

Mathematics
1 answer:
jekas [21]2 years ago
6 0

Answer:

507

Step-by-step explanation:

26 x 39 = 1014

/2

507

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Determine the angle at the centre of a circle with radius 12.0 cm for an arc length of of 21.0 cm.
nata0808 [166]

Answer:

\theta=\dfrac{7}{4}\ \text{radian}

Step-by-step explanation:

We have,

Radius of the circle is 12 cm

Arc length, l = 21 cm

It is required to find the central angle of the circle. The formula for the length of an arc of a circle is :

l=r\times \theta

\theta is central angle

\theta=\dfrac{l}{r}\\\\\theta=\dfrac{21}{12}\\\\\theta=\dfrac{7}{4}\ \text{radian}

So, the angle at the centre of the circle is \dfrac{7}{4}\ \text{radian}.

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2 years ago
bruce has a pet worm that fell into a well. the well is 37 feet deep. each day, the worm climbs up 7 feet, but each night, it sl
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In 24 hours, the worm climbs 5 feet.

7-2= 5 (the worm falls 2 feet every night)


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5*8=40 

It will take bruce's worm about 8 days to get to the top of the well. 

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3 years ago
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If I have 9 employees and only 5 of them worked. What is my percentage
Charra [1.4K]
Percentage of working employees is 55.56
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3 years ago
What is the abscissa of the midpoint of the line segment whose endpoints are (5√2,2√3) and (√2,2√3)
xxMikexx [17]
Let
A------> <span>(5√2,2√3)
B------> </span><span>(√2,2√3)

we know that
</span>the abscissa<span> and the ordinate are respectively the first and second coordinate of a point in a coordinate system</span>
the abscissa is the coordinate x<span>

step 1
find the midpoint
ABx------> midpoint AB in the coordinate x
</span>ABy------> midpoint AB in the coordinate y
<span>
ABx=[5</span>√2+√2]/2------> 6√2/2-----> 3√2
ABy=[2√3+2√3]/2------> 4√3/2-----> 2√3

the midpoint AB is (3√2,2√3)

the answer is
the abscissa of the midpoint of the line segment  is 3√2

see the attached figure

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3 years ago
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HELP ME ON THIS QUESTION ASAP!!!!!
Naya [18.7K]
The answer is 2

Y2-Y1 / X2-X1
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3 years ago
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