Answer:
a. engranaje 1 → engranaje 2 → engranaje 3 → engranaje 4
z1 = 10 z2 = 20 z3 =10 z4 = 20
b. n2 = 600 rpm, n3 = 1200 rpm, n4 = 600 rpm
la relacion de transmision = 2
Explanation:
where z1 = 10, z2 = 20, z3 = 10, z4 = 20
and n1 = 1200 rpm
n2 = n1 * z1/z2 = (1200 * 10)/ 20 = 600 rpm
n3 = n2 * z2/z3 = (600 * 20)/ 10 = 1200 rpm
n4 = n3 * z3/z4 = (1200 * 10)/ 20 = 600 rpm
la relacion de transmision = z2/z1 * z3/z2 * z4/z3
= 20/10 * 10/20 * 20/10 = 2 * 0.5 * 2 = 2
Where ARE the books that you borrowed?
A writer maybe, because you can work by yourself, even at home.
Answer:
In general the number of bit registers in Intel 80x86 CPU design when combined together forms a 16 - bit register
An example of the -bit registers are AH, AL, BH, BL, CH, CL, DH, and DL
Explanation:
Solution
The 8086 CPU design has a total of eight 8-bit registers and these register can be integrated together to make 16- bit register as well.
The 16-bit data is stored by breaking the data into a low-order byte and high order byte.
The name of the 8 bit registers is shown below:
AH, AL, BH, BL, CH, CL, DH, and DL
