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docker41 [41]
3 years ago
5

How do you work out px+py=a?

Mathematics
1 answer:
natka813 [3]3 years ago
5 0
\bf px+py=a\implies \stackrel{\textit{common factor}}{p}(x+y)=a\implies p=\cfrac{a}{x+y}
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What is the domain and range of the function f(x) = x^2 -4x-5?
Tems11 [23]
F(x) = x²-4x-5, quadratic function,  
Domain (the values if x) is all real numbers.

To find range we should draw a graph or to write an equation in vertex form.
f(x) = x²-4x+4-4-5
f(x) = (x-2)²-9
Point (-2,-9) is the vertex of the parabola, and it is a minimum because a parabola has positive sign in front of x², so it is looking up.  Minimum value of y =-9
Range(the values of y) is [-9, ∞)


5 0
3 years ago
In the diagram below, AB and TC are tangent to 0. Which equation could be solved to find x, the measure of AC?
LekaFEV [45]

The  equation that could be solved to find x, the measure of AC is 58 = 1/2(238 -x)

<h3>Circle theorem</h3>

The given diagram shows two intersecting lines tangential to a circle at points A and C.

Using the theorem that states, the measure of the angle at the vertex is equal to the half of the difference of the measure of the intercepted arcs.

Mathematically;

<B = 1/2(arcADC - arcAC)

58 = 1/2(238 -x)

Hence the  equation that could be solved to find x, the measure of AC is 58 = 1/2(238 -x)

Learn more on circle theorem here: brainly.com/question/26594685

#SPJ1

4 0
1 year ago
Helppp plsssss someone D:
zimovet [89]
〽Hola User_______________

⭐Here is Your Answer..!!!

______________________

↪Cartesian Coordinates of the system....!!

↪X = rcos⊙ and Y = rsin⊙

↪since here Radius (r) = 10 units and Theta (⊙) = 225°

↪there fore substituting we get as ..

↪X = 10 ( cos 225° ) = 10 * -1/ root 2 = -7.071

↪Y = 10 ( sin 225° ) = 10 * -1/root2 = = -7.071

↪the cordinates are as follows

↪(x,y) = (-7.071, -7.071 )
4 0
3 years ago
Da<br> A<br> Solve the equation 2x^2+3=0
Anika [276]

Answer:

x = ±i(√6 / 2)

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Equality Properties

<u>Algebra I</u>

  • Solving quadratics

<u>Algebra II</u>

Imaginary root i

  • √-1 = i

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

2x² + 3 = 0

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. [Subtraction Property of Equality] Subtract 3 on both sides:                        2x² = -3
  2. [Division Property of Equality] Divide 2 on both sides:                                  x² = -3/2
  3. [Equality Property] Square root both sides:                                                    x = ±√(-3/2)
  4. Simplify:                                                                                                             x = ±i(√6 / 2)
4 0
3 years ago
Solve the equation. –x 8 3x = x – 6 x = –18 x = –14 x = 2 x = 4
LenKa [72]

The value of the variable x in the equation –x + 8 + 3x = x – 6 is - 14.

<h3>How to find variable in an equation?</h3>

The variables of an equation can be found as follows:

–x + 8 + 3x = x – 6

The variable in the equation is x.

Therefore,

–x + 8 + 3x = x – 6

combine like terms on the left side

-x + 3x + 8 = x - 6

2x + 8 = x - 6

subtract x form both sides of the equation

2x - x + 8 = - 6

x + 8 = -6

subtract 8 from both sides

x = -6 - 8

x = - 14

learn more on equation here: brainly.com/question/1347990

#SPJ4

3 0
2 years ago
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