Answer:
%30 off is the better price
Step-by-step explanation:
firstly we know that 2 - 12 is equal to 10 so that is $10.00 there from that coupon
to find out the second value, we first devide by the total amount (%100 in this case)
<em>12 / 100 = 10.12</em>
then we multiply by the partial amount (%30)
<em>0.12 * 30 = 3.6</em>
convert that into a dollar amount and we get the total discount in dollars
<em>3.60 = $3.60</em>
AND
<em>$3.60 > $2.00</em>
<em />
hope this helps ya, take care mate :D
Answer:
Step-by-step explanation:
-7x + 12 + (-8x + 48) = 180
-15x + 60 = 180
-15x = 120
x = -8
m<BDC= -7(-8)+ 12 = 56 + 12 = 68
m<CBA = -8(-8)+48 = 64+48 = 112
If George's driveway is a rectangle 12.2 m by 3.0 m, its dimensions in cm are
... 1220 cm long × 300 cm wide × 2 cm deep
Thus the volume of gravel required is
... (1220 × 300 × 2) cm³ = 732,000 cm³
George needs about 0.732 bags, so he will probably need to buy 1 bag.
The estimate of the number of students studying abroad in 2003 is 169 and the estimate of the number of students studying abroad in 2018 is 433
<h3>a. Estimate the number of students studying abroad in 2003.</h3>
The function is given as:
y = 123(1.065)^x
Where x represents years from 1998 to 2013
2003 is 5 years from 1998.
This means that
x = 5
Substitute the known values in the above equation
y = 123(1.065)^5
Evaluate the exponent
y = 123 * 1.37008666342
Evaluate the product
y = 168.520659601
Approximate
y = 169
Hence, the estimate of the number of students studying abroad in 2003 is 169
<h3>b. Assuming this equation continues to be valid in the future, use this equation to predict the number of students studying abroad in 2018.</h3>
2018 is 20 years from 1998.
This means that
x = 20
Substitute the known values in the above equation
y = 123(1.065)^20
Evaluate the exponent
y = 123 * 3.52364506352
Evaluate the product
y = 433.408342813
Approximate
y = 433
Hence, the estimate of the number of students studying abroad in 2018 is 433
Read more about exponential functions at:
brainly.com/question/11464095
#SPJ1
