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Sladkaya [172]
3 years ago
9

Describe the relationship between predator and prey in a balanced ecosystem. Please hellppp.

Chemistry
1 answer:
Umnica [9.8K]3 years ago
3 0

Answer:without predators, to keep prey from producing too many and over eating, the ecosystem suffers as there isn’t enough for the prey themselves to eat.

Explanation:

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How many grams of water are needed to dissolve 27.8 g of ammonium nitrate?
andreyandreev [35.5K]
The moles of ammonium nitrate needed to dissolve 0.35 moles
The moles of water that will react is 0.35 moles as due to ratio
so mass of water will be 0.35 x 18=6.3g 
                                 MASS OF WATER WILL BE 6.3 g
7 0
4 years ago
What is an example of making an inference to support comprehension? In three to five sentences, explain your answer. 20 points
Elena-2011 [213]

Answer:

For example, a student looking at the picture of the baby could state the obvious by saying the baby is crying. ... When students predict, they guess what will happen next based on what they already know from the text and their background knowledge. When students infer, they make a guess about what is currently happening.

Explanation:

Hope that helps

Have I good day

Can I have brain pls

8 0
3 years ago
Which acid is the best choice to create a buffer with ph= 3.19?
Crazy boy [7]
<span>The best choice is hypochlorous acid nitrous acid (HNO2) because it has the nearest value of pK to the desired pH.
pKa of </span>nitrous acid<span> is 3.34 
If we know pKa and pH values,  we can calculate the required ratio of conjugate base (NO2⁻) to acid (HNO2) from the following equation:
pH=pKa + log(conc. of base)/( conc. of acid)
</span><span>3.19=3.34 + log c(NO2⁻)/c(HNO2)
</span><span>3.19 - 3.34 = log c(NO2⁻)/c(HNO2)
-0.15 = log c(NO2⁻)/c(HNO2)
c(NO2⁻)/c(HNO2) = 10⁰¹⁵ = 1.41

</span>
5 0
4 years ago
Based on silicon's position on the periodic table, it has
monitta
A. 
The first energy level has 2 electrons, the second has 8, and the third has 4
5 0
4 years ago
Read 2 more answers
What is the approximate mass of 25 cm3 of silver, if the density is 10.5 g/cm3? A. 0.42 g B. 2.4 g C. 42 g D. 260 g
bulgar [2K]

A."0.42"

or


D. but this formula is weird we take the mass 25 multiply by 10.5 we get 262.5

A. we divide 25 / 10.5 we get 0.42

it 50/50

Hope i can help at least little











6 0
3 years ago
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