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NeTakaya
2 years ago
9

Can be generally defined as a change in position OA. Mass OB. Force OC. Volume OD. Motion Reset​

Chemistry
2 answers:
labwork [276]2 years ago
7 0

Answer:

Not sure were to start....

Explanation:

bogdanovich [222]2 years ago
7 0

Answer: motion

Explanation: hope this helps you

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Which has more particles, a mole of copper (Cu) atoms or a mole of neon
goldfiish [28.3K]

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D

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it is neon because neon has a higher atomic number so it would have more protons and neutrons and electrons in one atom thus having more particles in one mole

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3 years ago
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What is the word that means "these break food into pieces
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Your digestive system
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PLEASE HELP ASAP
swat32

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Fe is the limiting reagent

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3 years ago
Consider the reaction 4PH3(g) → P4(g) + 6H2(g) At a particular point during the reaction, molecular hydrogen is being formed at
Svetllana [295]

Answer:

The rate at which P_4 is being produced is 0.0228 M/s.

The rate at which PH_3 is being consumed is 0.0912 M/s.

Explanation:

4PH_3\rightarrow P_4(g)+6H_2(g)

Rate of the reaction : R

R=\frac{-1}{4}\frac{d[PH_3]}{dt}=\frac{1}{6}\frac{d[H_2]}{dt}=\frac{1}{1}\frac{d[P_4]}{dt}

The rate at which hydrogen is being formed = \frac{d[H_2]}{dt}=0.137 M/s

R=\frac{1}{6}\frac{d[H_2]}{dt}

R=\frac{1}{6}\times 0.137 M/s=0.0228 M/s

The rate at which P_4 is being produced:

R=\frac{1}{1}\frac{d[P_4]}{dt}

0.0228 M/s=\frac{1}{1}\frac{d[P_4]}{dt}

The rate at which PH_3 is being consumed :

R=\frac{-1}{4}\frac{d[PH_3]}{dt}

0.0228 M/s\times 4=\frac{-1}{1}\frac{d[PH_3]}{dt}

\frac{-1}{1}\frac{d[PH_3]}{dt}=0.912 M/s

6 0
3 years ago
PLEASE HELP ASAP If an aluminum bar has a mass of 34.9 g and a density of 3.8 g/mL, what is the volume?
nasty-shy [4]

Answer:

92 cm^3

Explanation:

3 0
3 years ago
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