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svp [43]
2 years ago
9

Cindy runs 2 km every morning. She takes 2 minutes for the first 250 meters, 4 minutes for the next $1, 000 meters, one minute f

or the next 350 meters, and three minutes for the rest.
Cindy's average speed for the entire run is _____ meters per minute. 1 km is the same as 1000.
Chemistry
1 answer:
ser-zykov [4K]2 years ago
8 0

Her adverage speed would be 160 meters per second!


If you feel the answer is incorrect please comment and I will revise! Have a good day!



Proof:

2 minutes=250 meters

6 minutes=1,250 meters

7 minutes=1,600 meters

10 minutes= 1,600 meters

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Whitepunk [10]
<h2>Answer:</h2><h3>Part 1. </h3>

Option B is correct option.

The half-reaction 2MnO2 + H2O + 2e- Mn2O3 is missing  OH- ions.

Explanation:

Full equation:

                                          2MnO2 + H2O + 2e-  → Mn2O3 + 2OH-

<h3>Part 2:</h3>

The option B which is Mg is stronger reducing agent than Ag is correct option.

Explanation:

Equation:

                               Mg(s) + 2Ag+ (aq) → Mg2+ (aq) + 2Ag(s)

According to equation Mg converts to Mg+2 which means it gives to electron to reduce Ag. So it act as an reducing agent.

<h3>Part 3:</h3>

The correct option is B. Which is  5, 1, 8, 5, 1, 4.

Explanation:

Full equation :

                  5 Fe²⁺ (aq) + MnO₄⁻ (aq) + 8 H⁺ (aq) --> 5 Fe³⁺ (aq) + Mn²⁺ (aq) + 4 H₂O (l)


<h3 />

5 0
3 years ago
‼️SHOW ALL STEPS‼️ If 14.4 grams of iron reacts with hydrochloric acid, how many grams of hydrogen gas will be produced?
Alex Ar [27]

Answer: 0.771 g of H_2 will be produced

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Fe=\frac{14.4g}{56g/mol}=0.257moles

The balanced chemical reaction is:

2Fe(s)+6HCl(aq)\rightarrow 2FeCl_3(aq)+3H_2(g)  

According to stoichiometry :

2 moles of Fe produce = 3 moles of H_2

Thus 0.257 moles of Fe will produce=\frac{3}{2}\times 0.257=0.385moles  of H_2  

Mass of H_2=moles\times {\text {Molar mass}}=0.385moles\times 2g/mol=0.771g

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