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marissa [1.9K]
4 years ago
8

Prove the following equation: sin ( 90 + theta ) = cos theta . .

Mathematics
2 answers:
Mila [183]4 years ago
7 0
To prove this kind of equation you must use the Trigonometric Function of Equality. And came up with the formula of sin(x+y) = sin(x)*cos(y)+cos(x)*sin(y) and then substitute the variables that is present if your function and came up with an answer of sin(90-theta)=sin(90)*cos(theta)+cos(90)*sin(theta)=cos(theta)
I hope i answered your question
KIM [24]4 years ago
5 0
Using the trigonometric equality:

sin(x+y)=sin(x)*cos(y)+cos(x)*sin(y)

then:

<span>sin(90+θ)=sin(90)*cos(θ)+cos(90)*sin(θ)=cos(θ)</span>
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3 years ago
Use the intermediate value theorem to prove that there is a positive number c such that c2 = 2.
schepotkina [342]

So lets try to prove it,

So let's consider the function f(x) = x^2.

Since f(x) is a polynomial, then it is continuous on the interval (- infinity, + infinity).

Using the Intermediate Value Theorem,

it would be enough to show that at some point a f(x) is less than 2 and at some point b f(x) is greater than 2. For example, let a = 0 and b = 3.

Therefore, f(0) = 0, which is less than 2, and f(3) = 9, which is greater than 2. Applying IVT to f(x) = x^2 on the interval [0,3}.

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2 years ago
Find the exact length of the third side.<br> 10<br> 24
Nuetrik [128]

Step-by-step explanation:

10×10+24×24= third side ×third side

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3 years ago
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valentina_108 [34]

Answer:

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