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3 years ago

Suppose that y varies directly with x and y= 5 when x= 6. What is y when x= 5?

Mathematics

1 answer:

GenaCL600 [577]3 years ago

8 0

If y and x vary on one another and if we suppose y=5 and in relation x=6 then when x=5 y should be 4

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Combine like terms.<br> - 2x - 14 = -3.- 1

UNO [17]

Answer:

combine -3-1

$- 2x - 14 = - 4$

if you want to solve for x then you would move the -14 to the left buy adding 14 to both sides.

$- 2x - 14 = - 4 \\ \: \: \: \: \: \: \: \: \: \: \: + 14 \: \: + 14$

your equation there will be

$- 2x = 10$

then you will divide -2 on both sides

$\frac{ - 2x}{ - 2} = \frac{10}{ - 2}$

finally x will equal

$x = - 5$

3 0

2 years ago

What is 8114 divided by 46

Shkiper50 [21]

Answer:The answer can be calculated by doing the following

Steps;

Step-by-step explanation:

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2 years ago

3. A restaurant has 26 tables in its dining room. It takes the waitstaff 10 minutes to clear and set 4

antoniya [11.8K]

Answer:

2 hr and 58 min

Step-by-step explanation:

8 0

2 years ago

Given the vectors A⃗ and B⃗ shown in the figure ((Figure 1) ), determine the magnitude of B⃗ −A⃗. A is 28 degrees above the posi

Vlad [161]

This problem is represented in the Figure below. So, we can find the components of each vector as follows:

$\bullet \ cos(28^{\circ})=\frac{Adjacent}{Hypotenuse}=\frac{A_{x}}{44} \\ \\ \therefore A_{x}=44cos(28^{\circ})=38.85m \\ \\ \\ \bullet \ sin(28^{\circ})=\frac{Opposite}{Hypotenuse}=\frac{A_{y}}{44} \\ \\ \therefore A_{y}=44sin(28^{\circ})=20.65m$

$\bullet \ cos(56^{\circ})=\frac{Adjacent}{Hypotenuse}=\frac{-B_{x}}{26.5} \\ \\ \therefore B_{x}=-26.5cos(56^{\circ})=-14.81m \\ \\ \\ \bullet \ sin(56^{\circ})=\frac{Opposite}{Hypotenuse}=\frac{B_{y}}{26.5} \\ \\ \therefore B_{y}=26.5sin(56^{\circ})=21.97m$

Therefore:

$\vec{A}=(38.85, 20.65)m \\ \\ \vec{B}=(-14.81, 21.97)m$

So:

$\vec{B}-\vec{A}=(-14.81, 21.97)-(38.85, 20.65)=(-53.66,1.32)$

Finally, the magnitude is:

$\boxed{\left| \vec{B}-\vec{A}\right|=\sqrt{(-53.66)^2+(1.32)^2}=53.67m}$

7 0

2 years ago

Read 2 more answers

Simplify: x^2-49

Softa [21]

For x^2-49
this is a diffarence of two perfect squares. I suggest that this is memorised.
a^2-b^2=(a-b)(a+b)
so x^2-7^2=(x-7)(x+7)

so to solve x^2+x-56 you want to find out what two numbers add to 1 and multiply to make -56
since -56 is negative we know that the two number are difarent signs so that eliminatess answers B and D.
if we try answer C -8+7=-1 so the answer is not C because we want +1 not -1
then we see that 8+(-7)=1 so the answer is A

5 0

2 years ago

Read 2 more answers