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alex41 [277]
3 years ago
7

PLEASE HELP! A) (2m³)^4 B) (3a)²

Mathematics
1 answer:
Zina [86]3 years ago
4 0

Answer:

Step-by-step explanation:

A) (2m^3)^4

2times 2 times 2times 2 = 16

m^3 times m^3 times m^3 times m^3 = m^12

Hence, your answer is : 16m^12

B) (3a)^2

3 times 3 = 9

a times a = a^2

Hence, your answer is: 9a^2

Hope this helps!

Would really appreciate the Brainliest!

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Question 1= Can Kayla conclude that ∆ABC and ∆EDC are similar? Why or why not?
klasskru [66]
We know that 1 side is 100 and 1 angle is 90 degrees
we would need at least 1 more angle or 1 more side length to say that they are similar

no
but, if we asssume that DCB is a straignt line, then we can say that they are similar


2. if we say taht they are similar then DE=AB, so then 175=DE=AB
7 0
3 years ago
Find x so that a is parallel to b. (4x+11) , (8x+1)
yan [13]
4x + 11 = 8x + 1
        11 = 4x + 1
        10 = 4x
         /4    /4
       2.5 = x

X = 2.5
4 0
3 years ago
Given the function f(x) = 0.5|x – 4| – 3, for what values of x is f(x) = 7?
rosijanka [135]
7=0.5 |x-4| -3
+3                +3
10=0.5 |x-4|
10/0.5=0.5/0.5 |x-4|
20=|x-4|
             ^
-20=x-4   20=x-4
 +4    +4    +4    +4
-16=x       24=x

The answers are -16=x and 24=x

Hope this helps, an if it pleases you put as the brainliest answer!


7 0
3 years ago
Read 2 more answers
It takes Ernesto 3 minutes to jog a lap around the school track. How many laps can Ernesto complete in 15 minutes?
OLEGan [10]

Answer:

5 laps

Step-by-step explanation:

We can use ratios to solve

3 minutes        15 minutes

----------------- = ------------------------

1 lap                   x laps

Using cross products

3x = 15

Divide each side by 3

3x/3 = 15/3

x = 5

He can do 5 laps

6 0
3 years ago
Given f(1) = 2, f′(1) = 3, g(1) = 1, g′(1) = 5, compute the following values: (a) Compute h′(1) for h(x) = f(g(x)). ′1 (b) Compu
kvasek [131]

a. By the chain rule,

h'(x) = f'(g(x)) * g'(x)

h'(1) = f'(g(1)) * g'(1) = f'(1) * 1 = 3

b. I suspect there's a typo here somewhere, but if you really mean j(x) = f(x), and you're only supposed to find j(1), then

j(1) = f(1) = 2

Possibly you're supposed to instead find j'(1), in which case

j'(1) = f'(1) = 3

Or maybe j is defined like

j(x) = 1/f(x)

in which case the chain rule gives

j'(x) = -f'(x)/f(x)^2

j'(1) = -f'(1)/f(1)^2 = -3/2^2 = -3/4

c. By the chain rule,

k'(x) = g'(x)/g(x)

k'(1) = g'(1)/g(1) = 5/1 = 5

8 0
3 years ago
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