Answer:
The square cake is has a larger area by about 40.73 square inches
Step-by-step explanation:
Find the area of the top of each cake.
The square cake has an area of 81 sq inches, ( length x width = Area, the
length is 9)
The round cake has an area of 16π, which is about 50.27 square inches
(A = πr², here r is 4, radius is half the diameter)
81 - 16π = 81 - 50.27 = 40.73 square inches
Your answer would be 4379 members because at the very beginning you had started off with 4372 members, however as the months go by changes happen. On october, it changed by -10, meaning that 10 students left the school meaning 4372-10=4362 members remaining. Then there's november with -8, so you subtract 8 from your new total 4362-8=4354. Then december comes, and this time it's a positive number, so you have to add 23 to 4354, giving you a new total of 4377. Then there's january, and its back to a negative number so you subtract 12 from 4377, 4377-12=4365. Then february comes and it's a change of a positive number, so you add 3 to the 4365, giving you 4368. And then finally by march, it's another positive number so you add 11 to your total, giving you 4379 students which are now at school. So basically if it's a negative change, subtract from the total, and if it is a positive, add to it. And you have to continue with the total that you got from the previous change that you did. Hope this was helpful
The answer to this question would be: (6.5 , 8.5)
To answer this question, you need to determine the x and y distance of both point. From A point the distance would be:
X distance= 14-4= 10
Y distance= 10-8= 2
Making it into 1:3 ratio means that dividing the line into 4 parts then take 1 part from the point A, or 3 part from point B. From A point the distance would be 1/4 total distance
The location would be:
X= 4 + (10*1/4)= 6.5
Y= 8+ (2*1/4)= 8.5
(6.5 , 8.5)
<u>Question 6</u>
1)
,
, O is the midpoint of
,
(given)
2)
are right angles (perpendicular lines form right angles)
3)
are right triangles (a triangle with a right angle is a right triangle)
4)
(a midpoint splits a segment into two congruent parts)
5)
(LL)
<u>Question 7</u>
1)
are right angles), 
2)
(reflexive property)
3)
are right triangles (a triangle with a right angle is a right triangle)
4)
(LL)
5)
(CPCTC)
<u>Question 8</u>
1)
, point D bisects
(given)
2)
are right angles (perpendicular lines form right angles)
3)
are right triangles (a triangle with a right angle is a right triangle)
4)
(definition of a bisector)
5)
(reflexive property)
6)
(LL)
7)
(CPCTC)