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Romashka [77]
3 years ago
11

Kx-bf=fy/m solve for y

Mathematics
2 answers:
kiruha [24]3 years ago
8 0
So you need to isolate y:
First you multiply m on both sides:
m(Kx - bf) = fy
Then, you divide f on both sides:
\frac{(m(Kx-bf))}{f} = y
svetoff [14.1K]3 years ago
5 0
Multiply both sides by (m) and you get (mkx-mbf=fy)

Then divide both sides by (f) and you get ((mkx-mbf)/(f)) = y
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What are the real and complex solutions of the polynomial equation? x^3-8=0. with imaginary numbers
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Answer:

Solutions are 2,  -1 +  0.5 sqrt10 i  and -1 - 0.5 sqrt10 i

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Step-by-step explanation:

The real solution is x = 2:-

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x^3 = 8

x = cube root of 8 = 2

Note that a cubic equation must have  a total of 3 roots ( real and complex in this case).  We can find the 2 complex roots by using the following identity:-

a^3 - b^3 = (a - b)(a^2 + ab + b^2).

Here  a = x and b = 2 so we have

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To find the complex roots we solve x^2 + 2x + 4 = 0:-

Using the quadratic formula x = [-2 +/- sqrt(2^2 - 4*1*4)] / 2

= -1 +/- (sqrt( -10)) / 2

= -1 +  0.5 sqrt10 i  and -1 - 0.5 sqrt10 i

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