What is z minus 200754

Mathematics

1 answer:

Tom [10]3 years ago

3 0

What does z equal? Is there a picture you could add to this

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What is the answer to this problem (x+3)(x+5)

klasskru [66]

Easy, showing work,

using the method FOIL (First,Outer,Inner, Last)

Take, (x+3)(x+5) and multiply,

First,

x*x= $x^{2}$

Outer,

x*5=5x

Inner,

3*x=3x

Last,

3*5=15

Add the terms together,

$x^{2}$ +8x+15 ( $x^{2}$ +5x+3x+15)

Thus, your answer.

4 0

3 years ago

Read 2 more answers

Find maclaurin series

Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

$\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}$

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

$\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}$

The first 3 terms of the series are

$\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}$

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

$\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}$