Answer:
Number of fish in 2006 = 845 fishes (Approx.)
Step-by-step explanation:
Given;
Number of fish in 2000 = 1,150 fishes
Decreasing rate = 5% per year
Find:
Number of fish in 2006
Computation:
Exponential decay function:
F = P[1-r]ⁿ
Number of year = 2006 - 2000
Number of year = 6 year
Number of fish in 2006 = 1,150[1-5%]⁶
Number of fish in 2006 = 1,150[1-0.05]⁶
Number of fish in 2006 = 1,150[0.95]⁶
Number of fish in 2006 = 1,150[0.735]
Number of fish in 2006 = 845.25
Number of fish in 2006 = 845 fishes (Approx.)
Answer:
HMMM this? im not sure i hope this will help... Solve the equation: 7x 9 x x 7. ... 7. Graph the linear system and estimate the solution. x + y = 4 x y = 8 (, ) 4. Write the slope-intercept form of the line that passes through the point (5, 5) and has ... x. Find h(g()). 4 ... Simplify the given expression.xy(xy 5xy 7y ) 6x y 4 0x y 4xy 6x y 4 5xy 7y 6x y 4 5x y 7x y d. ... B 5. x log7 log4 5.
Step-by-step explanation:
2y-x=3/4(-y+1)first distribute
2y-x=-3/4y+3/4 get the y on one side
2y-x+3/4y=3/4 add 3/4y to both sides
2y+3/4y=3/4+x add x to both sides
11/4y=3/4+x now divide by 11/4 (both sides)
y=3/11+4/11x
y=3+4x/11
choice c is the answer
Well hey...
2.25 ÷ 2.17 = 1.03 people on square miles
