Answer:
$9$
Step-by-step explanation:
Given: Thea enters a positive integer into her calculator, then squares it, then presses the $\textcolor{blue}{\bf\circledast}$ key, then squares the result, then presses the $\textcolor{blue}{\bf\circledast}$ key again such that the calculator displays final number as $243$.
To find: number that Thea originally entered
Solution:
The final number is $243$.
As previously the $\textcolor{blue}{\bf\circledast}$ key was pressed,
the number before $243$ must be $324$.
As previously the number was squared, so the number before $324$ must be $18$.
As previously the $\textcolor{blue}{\bf\circledast}$ key was pressed,
the number before $18$ must be $81$
As previously the number was squared, so the number before $81$ must be $9$.
Answer:
A) −20
Step-by-step explanation:
−5/3 (−2/3 )(−18)
Multiply the first and second terms. A negative times a negative is a positive
-5/3 * -2/3 = 10/9
10/9 * -18
Rewriting for easier math
-18/9 * 10
-2 * 10
-20
The equation given in the question is
V = <span>2πr^2h
h = V/ </span>2πr^2
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1 is b and 2 is j and 3 is d
