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3 years ago

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If f and g are differentiable functions for all real values of x such that f(1) = 4, g(1) = 3, f '(3) = −5, f '(1) = −4, g '(1)

= −3, g '(3) = 2, then find h '(1) if h(x) = f(x) g(x).
See attached

1 answer:

worty [1.4K]3 years ago

7 0

Hello,

h(x)'=(f(x)*g(x))'=f'(x)*g(x)+f(x)*g'(x)
h(1)=f'(1)*g(1)+(f(1)*g'(1)=-4*3+4*(-3)=-24
Answer B

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A lot is in the shape of a triangle. One side is 100 ft longer than the shortest side, while the third side is 700 ft longer tha

vaieri [72.5K]

We have the next information

x= the shortest side measure

y= the second side measure

y=x+100

z= the third side measures

z=x+700

We know also that the perimeter is 2900 ft

Therefore the equation for the perimeter of the triangle will be

$P=x+y+z$ $2900=x+x+100+x+700$

we sum like terms

$2900=3x+800$

then we isolate the x

$3x=2900-800$ $3x=2100$ $x=\frac{2100}{3}=700$

therefore

x=700ft

y=700+100=800ft

z=700+700=1400ft

The lengths of the sides of the lote are 700 ,800, and 1400 ft,

8 0

1 year ago

The probability of winning a game is 40%. You play 60 times. How many times do you expect win? PLZZZZZ HELP MEEE!!!!

Molodets [167]

You espect wint the 40% of 60:
40% of 60=(40/100)*60=(40*60)/100=24

Answer: you expect win 24 times.

4 0

3 years ago

Read 2 more answers

Calculus question?

Ann [662]

Remark
If you don't start exactly the right way, you can get into all kinds of trouble. This is just one of those cases. I think the best way to start is to divide both terms by x^(1/2)

Step One
Divide both terms in the numerator by x^(1/2)
y= 6x^(1/2) + 3x^(5/2 - 1/2)
y =6x^(1/2) + 3x^(4/2)
y = 6x^(1/2) + 3x^2 Now differentiate that. It should be much easier.

Step Two
Differentiate the y in the last step.
y' = 6(1/2) x^(- 1/2) + 3*2 x^(2 - 1)
y' = 3x^(-1/2) + 6x I wonder if there's anything else you can do to this. If there is, I don't see it.

I suppose this is possible.
y' = 3/x^(1/2) + 6x

y' = $\frac{3 + 6x^{3/2}}{x^{1/2}}$

Frankly I like the first answer better, but you have a choice of both.

5 0

3 years ago

Determine the radius, to the nearest inch, of a large can of tuna fish that has a volume of 66 cubic

Mnenie [13.5K]

The radius of can is 2.524 inches

<em><u>Solution:</u></em>

Given that large can of tuna fish that has a volume of 66 cubic inches and a height of 3.3 inches

To find: Radius

Given a large can of tuna fish, we know that can is generally of cylinder shape, we can use the volume of cylinder formula,

<em><u>The volume of cylinder is given as:</u></em>

$\text{ volume of cylinder}= \pi r^{2} h$$

Where,

"r" is the radius of cylinder

"h" is the height of cylinder

$\pi$ is a constant equal to 3.14

Substituting the given values in above formula,

$66 = 3.14 \times r^2 \times 3.3\\\\66 = r^2 \times 10.362\\\\r^2 = \frac{66}{10.362}\\\\r^2 = 6.369\\\\r = 2.524$

Thus the radius of can is 2.524 inches

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3 years ago

How many triangles can be constructed with angles measuring 50º, 90º, and 40º?

NeX [460]

Answer: Infinite

Step-by-step explanation:

We know that in a triangle the sum of all the interior angles must be 180°.

The given angles 50º, 90º and 40º

The sum of the angles 50º+ 90º + 40º= 180°

Thus, a triangle is possible with the given measurement.,

Let there is another triangle with the given angles, then by AAA similarity criteria they are similar.

Similarly, all the triangles with the same measurements of the angles must be similar.

Therefore, there are infinite number of triangles can be possible with angles measuring 50º, 90º, and 40º.

6 0

3 years ago

Read 2 more answers