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3 years ago

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If f and g are differentiable functions for all real values of x such that f(1) = 4, g(1) = 3, f '(3) = −5, f '(1) = −4, g '(1)

= −3, g '(3) = 2, then find h '(1) if h(x) = f(x) g(x).
See attached

1 answer:

worty [1.4K]3 years ago

7 0

Hello,

h(x)'=(f(x)*g(x))'=f'(x)*g(x)+f(x)*g'(x)
h(1)=f'(1)*g(1)+(f(1)*g'(1)=-4*3+4*(-3)=-24
Answer B

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