Question

A cylindrical metal pipe has a diameter of 8.4 millimeters and a height of 10 millimeters. A hole cut out of the center has a diameter of 6 millimeters.
A smaller cylinder is cut out of a larger cylinder. The smaller cylinder has a diameter of 6 millimeters. The larger cylinder has a diameter of 8.4 millimeters. Both cylinders have a height of 10 millimeters.



What is the volume of metal in the pipe? Use 3.14 for and round the answer to the nearest tenth of a cubic millimeter.

Answer 1

Answer:

$271.3 mm^3$

Step-by-step explanation:

We have to find the volume of the hole and subtract it from the volume of the cylinder.

The volume of a cylinder is given as:

$V = \pi r^2h$

where r = radius

h = height

A cylindrical metal pipe has a diameter of 8.4 mm and a height of 10 mm.

Its radius is 4.2 mm. Therefore, its volume is:

$V = 3.14 * 4.2^2 * 10 = 553.9 mm^3$

A hole cut out of the center has a diameter of 6 mm. Its height is also 10 mm.

Its radius is 3 mm. Therefore, its volume is:

$V = 3.14 * 3^2 * 10 = 282.6 mm^3$

Therefore, the volume of metal in the pipe is:

$553.9 - 282.6 = 271.3 mm^3$

Answer 2

Answer:

B

Step-by-step explanation: