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Alexxandr [17]
3 years ago
5

A car that experiences no frictional force is started and caused to move. For the car to continue in that motion, the gas pedal

would have to be used:
at all times
infrequently
intermittently
not at all


A spacecraft is traveling in space far from any planets or stars. How much force is required to maintain the spacecraft's speed?
1/2 the mass of the spacecraft
1/4 the mass of the spacecraft
none
twice the mass of the spacecraft
Physics
2 answers:
grin007 [14]3 years ago
7 0
The first one is D. there will be nothing to stop it in the first place. the second one is C. in space, nothing can stop a moving object.
Masteriza [31]3 years ago
6 0

1) Answer D not at all

The car is not experiencing any frictional force so that implies that there is no force acting on the car once it starts motion. So, according law of inertia, the car will continue to move and no other force is required.

Friction force is the resistance force that opposes the motion of any object. It arises due to the contact of surfaces.

2) Answer C none

There is no force on any spaceship moving far from any planet. So, according to law of inertia the spacecraft will continue to move at same speed.

Law of inertia states that any object keeps in the state of motion or rest unless a non zero external force is applied on it.

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A 100-g toy car moves along a curved frictionless track. At first, the car runs along a flat horizontal segment with an initial
aleksandrvk [35]

Answer:

The final velocity of the car is 2.02 m/s

Explanation:

Hi there!

The kinetic energy of the car as it runs along the first flat horizontal segment can be calculated using the following equation:

KE = 1/2 · m · v²

Where:

KE =  kinetic energy

m = mass

v = velocity

Then, the initial kinetic energy will be:

KE = 1/2 · 0.100 kg · (2.77 m/s)²

KE = 0.384 J

When the car gains altitude, it gains potential energy. The amount of gained potential energy will be equal to the loss of kinetic energy. So let´s calculate the potential energy of the car as it reaches the top:

PE = m · g · h

Where:

PE = potential energy.

m = mass

g = acceleration due to gravity.

h = height.

PE = 0.100 kg · 9.8 m/s² · 0.184 m

PE = 0.180 J

Then, the final kinetic energy will be (0.384 J - 0.180 J) 0.204 J

Using the equation of kinetice energy, we can obtain the velocity of the car:

KE =  1/2 · m · v²

0.204 J = 1/2 · 0.100 kg · v²

2 · 0.204 J  / 0.100 kg = v²

v = 2.02 m/s

The final velocity of the car is 2.02 m/s

7 0
3 years ago
A toy car has a kinetic energy of 8 J. What is its kinetic energy after a frictional force of 0.5 N has acted on it for 6 m?
Nezavi [6.7K]

Answer:

Final kinetic energy, KE_f=5\ J  

Explanation:

It is given that,

Kinetic energy of toy car, KE_i = 8\ J

Frictional force, F = 0.5 N

Distance, d = 6 m

We need to find the kinetic energy after this frictional force has acted on it. We know that frictional force is an opposing force. The work done by the toy car is given by :

W=F\times d

W=-0.5\ N\times 6\ m

W = -3 J

We know that the work done is equal to the change in kinetic energy. Let KE_f is the final kinetic energy.

W=KE_f-KE_i

-3=KE_f-8

KE_f=5\ J

So, the final kinetic energy is the toy car is 5 J. Hence, this is the required solution.

7 0
3 years ago
2. In a tug of war contest, one person pulls with a force of 5 Newtons. Another person on the same team pulls with a force of 3
yuradex [85]

Answer:

8 newtons

Explanation:

Balanced forces have an equal amount of newtons. 5+3=8, so the other team will need 8 newtons.

5 0
3 years ago
Read 2 more answers
What’s the equation for the alpha decay of plutonium-244.
kvv77 [185]

Answer:

Pu-244 and 94  alpha decay = U -240 and 92

8 0
3 years ago
How much power does it take to lift 30.0 N 10.0 m high in 5.00 s?
Rudik [331]

Power = work/time = (Force times distance)/time

= (30N *10.0m)/5.00s = 300/5 = 60 Watts

7 0
4 years ago
Read 2 more answers
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