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Anna11 [10]
3 years ago
14

How much power does it take to lift 30.0 N 10.0 m high in 5.00 s?

Physics
2 answers:
Rudik [331]3 years ago
7 0

Power = work/time = (Force times distance)/time

= (30N *10.0m)/5.00s = 300/5 = 60 Watts

Anna007 [38]3 years ago
5 0

Answer: P = 60 W

Explanation: Power is the ratio of energy per unit time. Energy can also be substituted by work.

P = W / t

= 30 N ( 10 m) / 5.00 s

= 60 W

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A 0.15-m straight wire moves with a constant velocity of 7.0 m/s perpendicularly
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8 0
2 years ago
4. A 62.0-kg person, standing on the diving board, dives straight down into the water. Just before striking the water, her speed
Alekssandra [29.7K]

To solve this problem it is necessary to apply the concepts related to the Moment. The moment in terms of the Force and the time can be expressed as

\Delta P = F\Delta t

F = Force

\Delta t = Time

At the same time the moment can be expressed in terms of mass and velocity, mathematically it can be given as

P = m \Delta v

Where

m = Mass

\Delta v = Change in velocity

Our values are given as

\Delta t=1.65s

By equating the two equations we can find the Force,

F\Delta t = m\Delta v

F = \frac{m\Delta v}{\Delta t}

F = \frac{62(1.1-5.5)}{1.65}

Therefore, the net average force will be:

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7 0
3 years ago
A copper wire has a radius of 2.9 mm. When forces of a certain equal magnitude but opposite directions are applied to the ends o
REY [17]

Answer:

550000000N/m

Explanation:

Given that a copper wire has a radius of 2.9 mm. When forces of a certain equal magnitude but opposite directions are applied to the ends of the wire, the wire stretches by 5.0×10−3 of its original length.

Original length L = 0.005L

the strain = extension/ original length

the strain = 0.005L / L

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11 × 10^10 = stress / 0.005

Cross multiply

Stress = 11 × 10^10 × 0.005

Stress = 550 000000 N/m

Therefore, the tensile stress on the wire is 550000000 N/m.

7 0
3 years ago
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