Answer:
Granulosa cells
Explanation:
Foliculogenesis is a dynamic and complex process through which the follicle goes through many stages of development in a short period (approximately 60 days in humans and some chimpanzees).
The stages classification is based on morphological changes such as follicular size or diameter, the number of follicular cell layers, etcetera. These classifications might vary among authors but could be denominated as:
- De Graaf follicles (This is the one shown in the image)
Through each stage, there are certain modifications in the oocyte, follicular cells, and connective tissue. As the oocyte grows, the follicular cells might reach a size twice or three times bigger than the ones of the primordial follicles. Their shape also changes and they adopt an aspect of stratified epithelium. Their cytoplasm gets a granulous aspect, after what these cells receive the name of <u><em>granulous cells</em></u>. The De Graaf follicle characterizes for having a space named follicular antro that displaces the oocyte to one of the sides.
The oocyte at this point gets surrounded by <u>zona pellucida</u> and <u>corona radiata </u>.
The follicular antro (The highlighted structure) separates the oocyte from the externally located <u>granulosa cells</u> or follicular cells.
Your answer is going to be Hydrolysis
Famine- High population means more mouths to feed
Disease- Diseases usually spread more quickly with people who live closer( as it can just move from one person to the other)
War- People like to fight for land, resources, money, etc. And having more of those things mean they are more able to support families, communities, and more.
(Hope this helps a little)
Answer and Explanation:
<u>Cross:</u> aa Bb dd Ee x AA bb Dd Ee
We can calculate the probability of getting heterozygous individuals in the progeny by using the <u>product rule</u>. Assuming that these four genes <u>assort independently</u> (<em>events that occur independently from each other</em>), we can infer that the F1 will have the next genotypic proportions for each gene:
1) aa x AA
F1) 4/4=1 Aa
2) Bb x bb
F1) ½ bb
½ Bb
3) dd x Dd
F1) ½ dd
½ Dd
4) Ee x Ee
F1) ¼ EE
2/4 = ½ Ee
¼ ee
So, to know what the probability is that the F1 of being heterozygous for all loci, we must multiply the respective individual probabilities of getting a heterozygous genotype, like this:
1 Aa x ½ Bb x ½ Dd x ½ Ee = 1/8 AaBbDdEe
Answer:
It disappears because it serves no other purposes in any of the next steps