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2 years ago

A building has 4 stories that are each 15 feet high. A scale drawing has the height of the building at 5 inches.

Mathematics

2 answers:

zlopas [31]2 years ago

8 0

Every 1 inch is 12 feet.

Sindrei [870]2 years ago

7 0

1) a
The building is 4*15 = 60 feet = 720 inches high. The ratio is 720/5 = 144 

2) b 
The ratio is 9/(1/4) = 36. So 1 foot = 12 inches and 12/36 = 1/3 

3) c 
With a ratio of 1:72, a 7.5 inch wingspan represents 7.5*72 = 45 feet 

I hope this helps!

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choose two numbers from the list 3,4,6,12. Explain the difference between finding the greatest common factor and the least commo

zepelin [54]

3 & 6 - LCM = 3. 3's multiples are 3, 6, 9,12, 16, etc. 6's multiples are 6, 12, 18, etc. therefore, the least common multiple is 6.
GCF - 3's factors are 1, 3, and 6's factors 1, 2, 3. so the greatest common factor is 3.

6 0

3 years ago

There are 1500 students in a school. 65% are girls. How many girls are there in the school?

bonufazy [111]

Answer:

975 girls

Step-by-step explanation:

To find 65% of 1500, multiply 1500 by .65 (to convert percentages to decimals, just move a decimal point over two spaces).

1500*.65=975

You can check that this answer is right with logic. Most of the students will be girls (more than 50%) and 975 makes up most of 1500.

Someone else asked this same question a while ago, and you can find their explanation here brainly.com/question/969975

4 0

3 years ago

Read 2 more answers

The probability of event X is 30%. The probability of event Y is 40%. If events X and Y are mutually exclusive, what is the prob

Soloha48 [4]

The probability of event X or Y is P = 0.7, or, in percentage form, the probability is 70%.

<h3>How the get the probability of event X or Y?</h3>

First, two events are mutually exclusive if these events can't happen at the same time.

This means that if happens X, with a 30% of probability, then Y can't happen.

If happens Y, with a 40% of probability, then X can't happen.

Then the probability of X or Y (the probability that one of these two events happens, not both) is just the addition of the two individual probabilities.

Then we have:

P(X or Y) = 0.3 + 0.4 = 0.7

Or, in percent form, we get:

P(X or Y) = 70%

The probability of event X or Y is just 70%.

If you want to learn more about probability:

brainly.com/question/25870256

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7 0

2 years ago

A recent study suggested that 70% of all eligible voters will vote in the next presidential election. Suppose 20 eligible voters

natita [175]

Answer:

0.0479 = 4.79% probability that fewer than 11 of them will vote

Step-by-step explanation:

For each voter, there are only two possible outcomes. Either they will vote, or they will not. The probability of a voter voting is independent of any other voter, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

70% of all eligible voters will vote in the next presidential election.

This means that $p = 0.7$

20 eligible voters were randomly selected from the population of all eligible voters.

This means that $n = 20$

What is the probability that fewer than 11 of them will vote?

This is:

$P(X < 11) = P(X = 10) + P(X = 9) + P(X = 8) + P(X = 7) + P(X = 6) + P(X = 5) + P(X = 4) + P(X = 3) + P(X = 2) + P(X = 1) + P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{20,10}.(0.7)^{10}.(0.3)^{10} = 0.0308$

$P(X = 9) = C_{20,9}.(0.7)^{9}.(0.3)^{11} = 0.0120$

$P(X = 8) = C_{20,8}.(0.7)^{8}.(0.3)^{12} = 0.0039$

$P(X = 7) = C_{20,7}.(0.7)^{7}.(0.3)^{13} = 0.0010$

$P(X = 6) = C_{20,10}.(0.7)^{6}.(0.3)^{12} = 0.0002$

$P(X = 5) = C_{20,5}.(0.7)^{5}.(0.3)^{15} \approx 0$

The probability of 5 or less voting is very close to 0, so they will not affect the outcome. Then

$P(X < 11) = P(X = 10) + P(X = 9) + P(X = 8) + P(X = 7) + P(X = 6) + P(X = 5) + P(X = 4) + P(X = 3) + P(X = 2) + P(X = 1) + P(X = 0) = 0.0308 + 0.0120 + 0.0039 + 0.0010 + 0.0002 = 0.0479$

0.0479 = 4.79% probability that fewer than 11 of them will vote

8 0

3 years ago

Jim has 5 computer science books and 3 math books. he has room to arrange four of them on a shelf. he wants at least two compute

zysi [14]

Answer: There are 60 different ways that he can arrange the books.

Step-by-step explanation:

Since we have given that

Number of computer science books = 5

Number of math books = 3

Number of books selected = 4

Atleast Number of computer science = 2

Atleast number of math book = 1

According to question, he wants at least two computer science books and at least one math book, and he wants to keep the computer science books and the math books together.

So, Number of different ways that he can arrange the books is given by

$^5C_2\times ^3C_2+^5C_3\times ^3C_1\\\\=30+30\\\\=60$

Hence, there are 60 different ways that he can arrange the books.

8 0

3 years ago