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Tasya [4]
3 years ago
15

A building has 4 stories that are each 15 feet high. A scale drawing has the height of the building at 5 inches.

Mathematics
2 answers:
zlopas [31]3 years ago
8 0
Every 1 inch is 12 feet.
Sindrei [870]3 years ago
7 0
1) a 
<span>The building is 4*15 = 60 feet = 720 inches high. The ratio is 720/5 = 144 </span>

<span>2) b </span>
<span>The ratio is 9/(1/4) = 36. So 1 foot = 12 inches and 12/36 = 1/3 </span>

<span>3) c </span>
<span>With a ratio of 1:72, a 7.5 inch wingspan represents 7.5*72 = 45 feet </span>

<span>I hope this helps!</span>
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Answer:

$7,008

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6 0
3 years ago
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Two pyramids are similar. The volume of the larger pyramid is 125 mº and the volume of the smaller pyramid is 27 mº. The height
GREYUIT [131]

Answer:

5 m

Step-by-step explanation:

\sqrt[3]{125} = 5

3 0
3 years ago
A landscaper is planting a row of 10 shrubs along the walkway shown below. There must be one shrub at the very beginning and one
rewona [7]

Answer:

9d = 36

Step-by-step explanation:

See attachment for complete question

Length = 36ft

n = 10

From the question, we understand that one shrub must be at both ends.

Taking the first as a point of reference, we're left with:

(n - 1) * distance = 36

Substitute 10 for n and d for distance

(10 - 1) * d = 36

9 * d = 36

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Hence:

9d = 36 answers the question

4 0
4 years ago
A parcel delivery service will deliver a package only if the length plus girth (distance around) does not exceed 84 in. What are
Lesechka [4]

Answer:

a) \frac{28}{\pi} in

b) 28 in

c) 784 in²

Step-by-step explanation:

Let the length be 'L'

and the radius be 'r'

Thus, according to the question

L + 2πr = 84 in

L = 84 - 2πr   ............(1)

Volume of the cylinder, V = πr²L

substituting the value of L from 1, we get

V =  πr²(84 - 2πr)

or

V = 84πr² - 2π²r³

for points of maxima, differentiating the above equation and equating it to zero

\frac{dV}{dr}=\frac{d(84\pi r^2-2\pi^2 r^3))}{dr}

or

2(84)πr - 3(2)π²r² = 0

or

2πr(84 - 3πr) = 0

or

r = 0    and    84 - 3πr = 0

or

⇒ 3πr = 84

or

⇒ r = \frac{28}{\pi} in

since, the radius cannot be zero therefore, r = 0 is neglected

Therefore,

a) The radius of the largest cylindrical package = \frac{28}{\pi} in

b) from  (2)

L = 84 - 2πr

or

⇒ L = 84 - 2\pi\times\frac{28}{\pi}

or

⇒ L = 84 - 56 = 28 in

The length of the largest cylindrical package = 28 in

c ) The volume of the largest cylindrical package ,V = πr²L

= \pi\times\frac{28}{\pi}\times28

= 784 in²

7 0
3 years ago
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