Using google translate:
When photocopying a credential, it is first enlarged to triple and subsequently the resulting copy is halved. What is the final effect on the original credential? If the credentials is a rectangle of 10 by 6 cm. What area will you have in the first photocopy? And in the second?
Original: 10 by 6 cm ; Area = length * width = 10 x 6 = 60 cm²
first copy: enlarged to triple
10 x 3 = 30
6 x 3 = 18
30 x 18 = 540 cm²
second copy: halved
30 x 1/2 = 15
18 x 1/2 = 9
15 x 9 = 135 cm²
4/7 = y/5019....with y being yes votes
cross multiply
(7)(y) = (4)(5019)
7y = 20076
y = 20076/7
y = 2868 <=== yes votes
total of yes and no votes : 5019 + 2868 = 7887
Yes 2,1 is a solution of this problem
Answer:
In traffic, she drove for 3 hours
and After the traffic cleared she drove for 2 hours.
Explanation:
Given that the road trip was 136 miles;
The first part of the trip there was lots of traffic, she only averaged 16 mph;
The second part of the trip there was no traffic so she could drive 44 mph;
She traveled for a total of 5 hours;
let x represent the time in traffic when she traveled at 16 mph
the time the traffic is clear would be;
Recall that distance equals speed multiply by time;
substituting the values;
solving for x;
So;
Therefore, In traffic, she drove for 3 hours
and After the traffic cleared she drove for 2 hours.
For the answer to the question above,
<span>V(n) = a * b^n, where V(n) shows the value of boat after n years.
V(0) = 3500
V(2) = 2000
n = 0
V(0) = a * b^0 = 3500
a = 3500
V(2) = a * b^2
2000 = 3500 * b^2
b = sqrt (2000/3500)
b ≈ 0.76
V(n) = 3500 * 0.76^n
We can check it for n = 1 which is close to 2500 in the graph:
V(1) = 3500 * (0.76)^1
V(1) = 2660
And in the graph we have V(3) ≈ 1500,
V(n) = 3500 * (0.76)^3 ≈ 1536
Now n = 9.5
V(9.5) = 3500 * (0.76)^(9.5)
V(9.5) ≈ 258</span>
