The grams of Fe₂O₃ that are formed is 47.68 g
<u><em>calculation</em></u>
Step 1: write the equation for reaction
4 Fe +3O₂ → 2 Fe₂O₃
Step 2: find the moles of Fe
moles = mass÷ molar mass
= 33.4 g÷55.8 g/mol =0.5986 moles
Step 3 : use the mole ratio to determine the moles of Fe₂O₃
That is from equation above Fe:Fe₂O₃ is 4:2 therefore the moles of Fe₂O₃ is = 0.5986 moles x 2/4 =0.2993 moles
Step 4 : find the mass of Fe₂O₃
mass = mass x molar mass
The molar mass of Fe₂O₃ = (55.8 x 2 +(15.9 x3) = 159.3 g/mol
mass is therefore = 0.2993 moles x 159.3 g/mol =47.68 g
<u>Answer:</u> The mass of chlorine needed by the plant per day is 
<u>Explanation:</u>
We are given:
Volume o water treated per day = 25,000,000 gallons
Converting this volume from gallons to liters, we use the conversion factor:
1 gallon = 3.785 L
So, 
Amount of chlorine applied for disinfection = 10 mg/L
Applying unitary method:
For 1 L of water, the amount of chlorine applied is 10 mg
So, for 
of water, the amount of chlorine applied will be 
Hence, the mass of chlorine needed by the plant per day is
Answer:
2AlF₃ + 3Li₂O —> Al₂O₃ + 6LiF
Explanation:
AlF₃ + Li₂O —> Al₂O₃ + LiF
The above equation can be balanced as follow:
AlF₃ + Li₂O —> Al₂O₃ + LiF
There are 2 atoms of Al on the right side and 1 atom on the left side. It can be balance by writing 2 before AlF₃ as shown below:
2AlF₃ + Li₂O —> Al₂O₃ + LiF
There are 6 atoms of F on the left side and 1 atom on the right side. It can be balance by writing 6 before LiF as shown below:
2AlF₃ + Li₂O —> Al₂O₃ + 6LiF
There are 2 atoms of Li on the left side and 6 atoms on the right side. It can be balance by writing 3 before Li₂O as shown below:
2AlF₃ + 3Li₂O —> Al₂O₃ + 6LiF
Thus, the equation is balanced..!
The answer is the first one
Answer:
US₂
Explanation:
Uranium sulfide (US₂)
Uranium atomic symbol = U
Sulfur atomic symbol = S
Uranium valency = +4
Sulfur valency = -2
So;
Uranium sulfide (US₂)
