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Iteru [2.4K]
4 years ago
9

The mass number of an atom is equal to which of the following?

Chemistry
1 answer:
seropon [69]4 years ago
5 0

the answer is c, the number of protons plus the number of neutrons in a nucleus

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Cacti and succulents are better adapted
masha68 [24]

Answer:

answer is C

Explanation:

encourage the release of carbon dioxide from the stems

8 0
3 years ago
125 ml of nitrogen gas is collected at 70.0 degrees Celsius. The pressure
dybincka [34]

Answer: Volume of the gas at STP is 22.53 L.

Explanation:

Given : Volume = 125 mL   (as 1 mL = 0.001 L) = 0.125 L

Temperature = 70^{o}C = (70 + 273) K = 343 K

Pressure = 125 kPa = 125 kPa \times \frac{0.01 atm}{1 kPa} = 1.25 atm

According to the ideal gas equation, the volume of given nitrogen gas is calculated as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

1.25 atm \times V = 1 mol \times 0.0821 L atm/mol K \times 343 K\\V = \frac{1 mol \times 0.0821 L atm/mol K \times 343 K}{1.25 atm}\\= \frac{28.1603}{1.25} L\\= 22.53 L

Hence, volume of the gas at STP is 22.53 L.

5 0
3 years ago
What’s the answer to this ( the proton has a ____ charge and it is found in the ____
Ksenya-84 [330]
ANSWER:

A proton has a "positive charge" and is found in the nucleus.

goodluck!!

support me by marking as brainliest!! :)
3 0
2 years ago
A rock is an
Gekata [30.6K]

Answer:

mineral

Explanation:

6 0
3 years ago
Read 2 more answers
If you have 12.5g of fluoride and 16.2g of sodium, which is the limiting reactant and how sodium fluoride in grams is your theor
Korvikt [17]

Answer:

F2 is the limiting reactant

27.6 grams of NaF is produced.

Explanation:

Balance the equation first.

2Na+ F2 ---> 2NaF

To find the limiting reactant, solve for how much NaF can be produced with Na and F2

12.5g F2 x (1 mole F2/ 38.00 grams F2)x (2 mole NaF/ 1 mole F2)

=0.658 moles NaF

16.2g Na x (1 mole Na/ 22.99 grams Na)x (2 mole NaF/ 2 mole Na)

=0.705 moles NaF

Since F2 produced the least NaF, F2 is the limiting reactant.

Now, to find how much NaF there is, use the moles solved above with F2 as the limiting reactant.

0.658 moles NaF x (41.99 grams NaF/ 1 mole NaF)= 27.6 moles NaF

27.6 moles of NaF would be theoretically produced.

8 0
3 years ago
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