Yes, when molten candle wax solidifies it is a chemical reaction
<u>Explanation:</u>
Basically Wax is crystalline so once the candle light melts it freezes taking back the solid state to the room temperature.
When the room temperature is below the freezing point, the liquid candle wax, turns into solid state again, therefore this process is called solidification. The process of freezing or solidification is a process when an object turns liquid and freezes back to solid state.
Indeed, Yes, when molten candle wax solidifies it is a chemical reaction
The <u>Mole</u> is the SI unit that expresses the amount of substance.
Mole is defined as - The mole is the amount of substance containing the same number of entities as there are in the 12 grams of Carbon - 12.
Mole is denoted by using symbol mol.
Mole = 6.022 x 10²³ elementary entities.
These number of elementary entities in 1 mole is equal to or called as an Avogadro's number. Mole is equal to 6.022 x 10²³ because this number of entity is same as in exactly 12 g of carbon-12.
It is a very important SI unit of measured which is used by the chemists. Moles are used in measuring in small or tiny things such as atoms, molecules and the other tiny particles.
To learn more about the mole concept,
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No of moles of Carbon, C = mass/ molar mass.
Molar mass of carbon = 12.0107. We only have to calculate the no of moles
of carbon to obtain carbon's mass. .
From Sucrose chemical formula C12H22O11 we know that there are 12
carbon atoms.
So there are 1.4x10^(20) x12 = 16.8 x 10^20 carbon atoms.
We will use avogardo's number to find out the number of carbon molecules
in the compound.
From Avogadro's no. One mole of any substance equals to 6.022140857
atoms.
So X mole contains 16.8 * 10^(20) carbon atom
(16.8x10^20 carbon atoms)/6.022 x10^23 particles/mol = 0.00279 mols
The molar mass of carbon is 12.0107g/mol so we'll multiply to get the mass:
0.00279 mols x 12 = 0.03348.
Atomic mass = number of protons + number of neutrons
= 10 + 8 = 18
In short, Your Answer would be Option C
Hope this helps!
