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2 years ago

Please answer question #4

Chemistry

2 answers:

mixer [17]2 years ago

8 0

Answer:

force = 1500N
work done = 15000 joules

Explanation:

Force = mass × acceleration

Force = 500 × 3 = 1500 Newtons

work done = force × displacement

Work done = 1500 × 10 = 15000j = 15kj

( j = joule, kj = kilo joules )

trasher [3.6K]2 years ago

7 0

Answer:

F=500×3 = 1500 N

W = 1500×10 =15000 Nm

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What is the maximum number of moles of N-acetyl-p-toluidine can be prepared from 70. milliliters of 0.167 M p-toluidine hydrochl

Kitty [74]

Answer:

$\large \boxed{\text{0.012 mol}}$

Explanation:

We will need a balanced equation with moles, so let's gather all the information in one place.

CH₃C₆H₄NH₂·HCl + (CH₃CO)₂O ⟶ CH₃C₆H₄NHCOCH₃ + junk

V/mL: 70.

c/mol·L⁻¹: 0.167

For simplicity in writing , let's call p-toluidine hydrochloride A and N-acetyl-<em>p</em>-toluidine B.

The equation is then

A + Ac₂O ⟶ B + junk

1. Moles of A

$\text{Moles of A} = \text{70. mL A}\times \dfrac{\text{0.167 mmol A}}{\text{1 mL A}}= \text{12 mmol A}$

2. Moles of B

The molar ratio is 1 mol B:1 mol A

Moles of B = moles of A = 12 mmol = 0.012 mol

$\text{You can prepare $\large \boxed{\textbf{0.012 mol}}$ of N-acetyl-p-toluidine. }$

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2 years ago

Malia was able to make a paperclip float on the surface of water. What will most likely happen to the paperclip if a drop of dis

Arturiano [62]

Answer:

Its A

Explanation:

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3 years ago

A 46.9 gram sample of a substance has a volume of about 3.5 centimeters3. It is solid at a room temperature of 23ºC. Out of the

horrorfan [7]

Answer : (C) Hafnium is the most likely identity of the given substance.

Solution : Given,

Mass of given substance (m) = 46.9 g

Volume of given substance (V) = 3.5 $Cm^{3}$

First, find the Density of given substance.

Formula used :

$Density=\frac{\text{Mass of given substance}}{\text{Voume of given substance}}$

Now,put all the values in this formula, we get

$Density=\frac{46.9 g}{3.5 Cm^{3} }$ = 13.4 g/ $Cm^{3}$

So, we conclude that the density of given substance (13.4 g/ $Cm^{3}$ ) is approximately equal to the density of Mercury and Hafnium (13.53 and 13.31 g/ $Cm^{3}$ respectively).

According to the question the substance is solid at room temperature but Mercury is liquid at room temperature. So, Mercury is not identical to the given substance.

Another element i.e, Hafnium is the element whose density is approximately equal to the given substance and also solid at room temperature. And we know that the melting point of solid is high.

So, Hafnium is the most likely element which is the identity of the given substance.

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2 years ago

Read 2 more answers

1. NaOH mass of a solution of 200g in which its percentage is 25%. What mass of sulfuric acid solution is needed to completely n

Ede4ka [16]

Answer:

$m_{H2SO4$ = 61.25 g

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Explanation:

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2 : 1 : 1 : 2

1.25 (moles)

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2 years ago

Why are the transition metals not isoelectronic with noble gas atoms?

V125BC [204]

The atoms and ions that have the similar electron configuration are named isoelectronic. The common ions of representative elements are isoelectronic with a noble gas. When forming ions, transition metals be unable to find their valence s-sublevel electrons before they lose their d-sub level electrons.

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