Answer:
Answer is 7. Did this is simple:
Step-by-step explanation:
(i) Sum the forces at point M in the x direction.
∑F = ma
-T sin 30° − T sin 30° + 5 N = 0
2T sin 30° = 5 N
T = 5 N
(ii) Sum the forces on the ring in the x direction.
∑F = ma
T sin 30° − N = 0
N = 2.5 N
Sum the forces on the ring in the y direction.
∑F = ma
T cos 30° − mg − Nμ = 0
Nμ = T cos 30° − mg
2.5 μ = 5 cos 30° − 2
μ = 0.932
(iii) Sum the forces on the ring in the y direction.
∑F = ma
T cos 30° − m₁g − m₂g + Nμ = 0
m₂g = T cos 30° − m₁g + Nμ
m (10) = 5 cos 30° − 2 + (2.5)(0.932)
m = 0.466 kg
Answer: The answer is D .
Step-by-step explanation:
Answer:
x + 4y
Step-by-step explanation:
(x∧2+8xy+16y∧2)∧(1/3) · (x+4y)∧(1/3) = ((x+4y)∧2 · (x+4y))∧(1/3) = ((x+4y)∧3)∧(1/3)=
= (x+4y)∧(3/3) = x+4y
Good luck!!!
Common ratio = 28/7 = 4
8th term = (first term)4^7 = 114688
