Assuming that all the grapes have the same probability of being randomly picked:
<h3>
How to find the probabilities?</h3>
We know that there are 8 green grapes and 15 red grapes on the bowl, so there is a total of 23 grapes.
a) Here we need to find the probability that both grapes are green. Remember that the probability of getting a green grape is equal to the quotient between the number of green grapes and the total number of grapes, this is:
P = 8/23
But then he must take another, because he already took one, the number of green grapes is 7, and the total number of grapes is 22, so for the second grape the probability is:
P' = 7/22.
The joint probability is the product of the two individual probabilities:
prob = (8/23)*(7/22) = 0.11
b) For the first green grape we know that the probability is:
P = 8/23
Then he must get a red grape. There are 15 red grapes and 22 grapes in total, so the probability is:
P' = 15/22
Then the joint probability is:
prob = (8/23)*(15/22) = 0.24
If you want to learn more about probability:
brainly.com/question/25870256
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Answer:
d/t
D= Distance
T= Time
Step-by-step explanation:
It’s organized and you can see it more visually , gives you a way to double check and write down the data properly.
Answer:
Answer:
a).
The amount spent on school materials for each term of all ST201students
b).
a).
It is not a random sample. This looks like a convenience sampling and there is sampling bias. This sample is not representative of the entire population. Since it is not a random sample it is not appropriate to generalize the results to all students.
b).
The sample size is 80 which is greater than 30. It is large enough to assume normal distribution according to central limit theorem.
c).
mean: $617
z critical value at 95%: 1.96
standard error = σ/sqrt(n) =500/sqrt(80) = 55.9017
lower limit= mean-1.96*se = 617-1.96*55.9017=507.43
upper limit= mean+1.96*se = 617+1.96*55.9017=726.57
d).
The amount spent on school materials for each term for the 80 ST201students is $617. We are 95% confident that amount spent on school materials for each term of all ST201students falls in the interval ($507.43, $726.57).
Step-by-step explanation:
p<321
The number of people the auditorium can sit is less than 321.
Hope I helped :)
