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Klio2033 [76]
3 years ago
8

P9. Consider the discussion in Section 1.3 of packet switching versus circuit switching in which an example is provided with a 1

Mbps link. Users are generating data at a rate of 100 kbps when busy, but are busy generating data only with probability p = 0.1. Suppose that the 1 Mbps link is replaced by a 1Gbps link. (a) What is N, the maximum number of users that can be supported simultaneously under circuit switching?
Mathematics
1 answer:
Makovka662 [10]3 years ago
5 0

Answer:

  10,000

Step-by-step explanation:

The link capacity is 10^9 bps; the link usage is 10^5 bps per user, so the number of users that can be supported is ...

  (10^9 bps)/(10^5 bps/user) = 10^4 users

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4 0
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Further mathematics: Find the derivative of the function x^2 y + (xy)^3 +3x=0 at (-1 , 3)​
vesna_86 [32]

Answer:

3.

Step-by-step explanation:

Implicit differentiation:

x^2 y + (xy)^3 + 3x = 0

x^2 y + x^3y^3 + 3x = 0

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2x* y + x^2*dy/dx + 3x^2 y^3 + x^3* (d(y^3)/dx) + 3 = 0

2xy + x^2 dy/dx + 3x^2 y^3 + x^3* 3y^2 dy/dx + 3 = 0

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= -78/-26

=  3.

8 0
2 years ago
Read 2 more answers
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