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mars1129 [50]
3 years ago
13

On a given day, machine A has a 10% chance of malfunctioning and machine B has a 7% chance of the same. Given that at least one

of the machines malfunctioned today, what is the chance that machine B malfunctioned?
Mathematics
1 answer:
valentinak56 [21]3 years ago
4 0
I will give an instance to answer this. Suppose that we have 1,000 days. And it was given above that machine A has 10 % chances to malfunctioned and B has a 7%.  So machine A has 100 days that malfunctioned while machine B has 70 days. And 7 days that both machines malfunctioned (10%x7%). Next is to add 100 days from machine A and 70 days from machine B and subtract with the 7 days where both of them malfunctioned. So the result is 163 days out of 1000 that we expect an incidence of failure. So the chance of machine B to malfunctioned is 70 days. 70/163 is 42.93% 

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Use the drawing tool(s) to form the correct answer on the provided graph.
Dominik [7]

Answer:

  see below. The solution is the doubly-shaded area.

Step-by-step explanation:

Each boundary line will be dashed, because the "or equal to" case is <em>not included</em>. Each shaded area will be above the corresponding boundary line because the comparison symbol is y > .... That is, only y-values greater than (above) those in the boundary line are part of the solution.

Of course, the boundary lines are graphed in the usual way. Each crosses the y-axis at the value of the constant in its equation. Each has a slope (rise/run) that is the value of the x-coefficient in the equation.

3 0
3 years ago
Read 2 more answers
PLEASE HELP DUE TOMORROW 1. An artist is selling children’s crafts. Necklaces cost 2.25 each and bracelets cost 1.50 per each. a
Tems11 [23]

Answer:

Kindly check explanation

Step-by-step explanation:

Given that:

Cost per bracelet = 1.50

Cost per necklace = 2.25

Let :

number of necklace = n

Number of bracelet = b

Cost equation C ;

C = 1.5b + 2.25n

Number of necklace that could be sold for exactly $12

5 necklaces and 1 bracelet :

1.5 + 2.25(5) = 12.75

•2 necklaces and 5 bracelets:

1.5(5) + 2.25(2) = 12

• 3 necklaces and 3 bracelets

1.5(3) + 2.25(3) = 11.25

• 4 necklaces and 2 bracelets

1.5(2) + 2.25(4) = 12

• 3 necklaces and 5 bracelets

1.5(5) + 2.25(3) = 14.25

• 6 necklaces and no bracelets •

1.5(0) + 2.25(6) = 13.5

No necklaces and 8 bracelets

1.5(8) + 2.25(0) = 12

Amount charged per Tshirt = c

Setup fee = $40

Number of students in drama club = 21

Total cost of order = $187

Calculate C ;

Total order cost = set up fee + (cost per shirt * number of shirts)

Total order cost = 40 + 21c

187 = 40 + 21c

187 - 40 = 21c

147 = 21c

c = 147 / 21

C = 7

Hence cost per shirt = $7

5 0
3 years ago
Is the solution of this equation extraneous?
UkoKoshka [18]

Answer:

x = - 3 is extraneous

Step-by-step explanation:

Given

\sqrt{x+7} - 1 = x  ( add 1 to both sides )

\sqrt{x+7} = x + 1 ( square both sides )

x + 7 = (x + 1)² ← distribute right side

x + 7 = x² + 2x + 1 ( subtract x + 7 from both sides )

0 = x² + x - 6 ← in standard form

0 = (x + 3)(x - 2) ← in factored form

Equate each factor to zero and solve for x

x + 3 = 0 ⇒ x = - 3

x - 2 = 0 ⇒ x = 2

As a check

Substitute these values into the equation and if both sides are equal then they are the solutions.

x = - 3 : \sqrt{-3+7} - 1 = \sqrt{4} - 1 = 2 - 1 = 1 ≠ - 3

x = 2 : \sqrt{2+7} - 1  = \sqrt{9} - 1 = 3 - 1 = 2

x = 2 is a solution and x = - 3 is extraneous

6 0
3 years ago
Read 2 more answers
Mr. Martin’s math test, which is worth 100 points, has 29 problems. Each problem is worth either 5 points or 2 points. Let x be
klio [65]
(x + y = 29)
(y = 29 - x)
(5x + 2(29 - x) = 100)
(5x + 58 - 2x = 100)
(3x = 42)
(x = 14)
(y = 15)
(14 5-point questions and 15 2-point questions)
6 0
3 years ago
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Terri Vogel, an amateur motorcycle racer, averages 129.71 seconds per 2.5 mile lap (in a 7 lap race) with a standard deviation o
Vikki [24]

Answer:

(a) The percent of her laps that are completed in less than 130 seconds is 55%.

(b) The fastest 3% of her laps are under 125.42 seconds.

(c) The middle 80% of her laps are from <u>126.80</u> seconds to <u>132.63</u> seconds.

Step-by-step explanation:

The random variable <em>X</em> is defined as the number of seconds for a randomly selected lap.

The random variable <em>X </em>is normally distributed with mean, <em>μ</em> = 129.71 seconds and standard deviation, <em>σ</em> = 2.28 seconds.

Thus, X\sim N(129.71,\ 2.28^{2}).

(a)

Compute the probability that a lap is completes in less than 130 seconds as follows:

P(X

                   =P(Z

The percentage is, 0.55 × 100 = 55%.

Thus, the percent of her laps that are completed in less than 130 seconds is 55%.

(b)

Let <em>x</em> represents the 3rd percentile.

That is, P (X < x) = 0.03.

⇒ P (Z < z) = 0.03

The value of <em>z</em> for the above probability is:

<em>z</em> = -1.88

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\-1.88=\frac{x-129.71}{2.28}\\x=129.71-(1.88\times 2.28)\\x=125.4236\\x\approx 125.42

Thus, the fastest 3% of her laps are under 125.42 seconds.

(c)

Let <em>x</em>₁ and <em>x</em>₂ be the values between which the middle 80% of the distribution lie.

That is,

P(x_{1}

The value of <em>z</em> for the above probability is:

<em>z</em> = 1.28

Compute the values of <em>x</em>₁ and <em>x</em>₂ as follows:

-z=\frac{x_{1}-\mu}{\sigma}\\-1.28=\frac{x_{1}-129.71}{2.28}\\x_{1}=129.71-(1.28\times 2.28)\\x=126.7916\\x\approx 126.80               z=\frac{x_{2}-\mu}{\sigma}\\1.28=\frac{x_{2}-129.71}{2.28}\\x_{2}=129.71+(1.28\times 2.28)\\x=132.6284\\x\approx 132.63

Thus, the middle 80% of her laps are from <u>126.80</u> seconds to <u>132.63</u> seconds.

5 0
3 years ago
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