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mars1129 [50]
3 years ago
13

On a given day, machine A has a 10% chance of malfunctioning and machine B has a 7% chance of the same. Given that at least one

of the machines malfunctioned today, what is the chance that machine B malfunctioned?
Mathematics
1 answer:
valentinak56 [21]3 years ago
4 0
I will give an instance to answer this. Suppose that we have 1,000 days. And it was given above that machine A has 10 % chances to malfunctioned and B has a 7%.  So machine A has 100 days that malfunctioned while machine B has 70 days. And 7 days that both machines malfunctioned (10%x7%). Next is to add 100 days from machine A and 70 days from machine B and subtract with the 7 days where both of them malfunctioned. So the result is 163 days out of 1000 that we expect an incidence of failure. So the chance of machine B to malfunctioned is 70 days. 70/163 is 42.93% 

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Step-by-step explanation:

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Aloiza [94]
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3 years ago
Find the unit rate 6 and 2/5 revolutions in 2 and 2/3 in seconds
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<u>Step 1</u>

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<u>Step 2</u>

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<u>Step 2 (A)</u>

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<u>Step 2 (B)</u>

Multiply 1st fraction to the reciprocal of the 2nd fraction

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Step-by-step explanation:

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